Aptitude - Problems on H.C.F and L.C.M - Discussion
Discussion Forum : Problems on H.C.F and L.C.M - General Questions (Q.No. 18)
18.
The ratio of two numbers is 3 : 4 and their H.C.F. is 4. Their L.C.M. is:
Answer: Option
Explanation:
Let the numbers be 3x and 4x. Then, their H.C.F. = x. So, x = 4.
So, the numbers 12 and 16.
L.C.M. of 12 and 16 = 48.
Discussion:
36 comments Page 4 of 4.
Arjun singh said:
1 decade ago
3x = 3 (4 H.C.F) = 12.
4x = 4 (4 H.C.F) = 16.
LCM of 12 & 16.
12 = 2*2*3.
16 = 2*2*2*2.
Now we have 2*2*3*2*2*2*2 = 192.
HCF = 4/LCM 192.
4/192 = 48 answer.
Got it or not.
4x = 4 (4 H.C.F) = 16.
LCM of 12 & 16.
12 = 2*2*3.
16 = 2*2*2*2.
Now we have 2*2*3*2*2*2*2 = 192.
HCF = 4/LCM 192.
4/192 = 48 answer.
Got it or not.
Neha said:
1 decade ago
You can't get 48 by 4/192 you can get 48 by 192/4.
Sukumar Satyen said:
1 decade ago
Let the numbers be 3x and 4x.
We know that 3x*4x = HCF*LCM.
=> 12x^2 = 4*LCM.
=> LCM = 3x^2.....equation (1).
L.C.M. of 3x, 4x = 12x.....equation (2).
Now, equation(1) = equation(2).
=> 3x^2 = 12x.
=> x = 4.
=> L.C.M = 12x = 12*4 = 48.
Thanks.
We know that 3x*4x = HCF*LCM.
=> 12x^2 = 4*LCM.
=> LCM = 3x^2.....equation (1).
L.C.M. of 3x, 4x = 12x.....equation (2).
Now, equation(1) = equation(2).
=> 3x^2 = 12x.
=> x = 4.
=> L.C.M = 12x = 12*4 = 48.
Thanks.
Homay said:
1 decade ago
HCF = 4 (given).
Say m = 4.
LCM = Product of two numbers/HCF.
= 3m*4m/m.
= 12*16/4.
= 48.
Say m = 4.
LCM = Product of two numbers/HCF.
= 3m*4m/m.
= 12*16/4.
= 48.
Kuldeep said:
1 decade ago
The product of two numbers is 724 and HCF is 4 then find the LCM?
ANUPAM KUMAR YADAV said:
1 decade ago
The sum of two number is 420 and one of them is 260. Find the product of the two numbers.
Find the greatest number of 4 digits which is divisible by 35.
Find the greatest number of 4 digits which is divisible by 35.
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