Aptitude - Problems on H.C.F and L.C.M - Discussion
Discussion Forum : Problems on H.C.F and L.C.M - General Questions (Q.No. 29)
29.
| The H.C.F. of | 9 | , | 12 | , | 18 | and | 21 | is: |
| 10 | 25 | 35 | 40 |
Answer: Option
Explanation:
| Required H.C.F. = | H.C.F. of 9, 12, 18, 21 | = | 3 |
| L.C.M. of 10, 25, 35, 40 | 1400 |
Discussion:
29 comments Page 3 of 3.
Sirisha said:
1 decade ago
9/10, 12/25, 18/35, 21/40 is the given problem.
H.C.F of numerators,
9 = 3*3.
12 = 3*2*2.
18 = 2*3*3.
21 = 7*3.
Common least factors of these numbers is 3(h.c.f).
L.C.M of denominators,
10 = 2*5.
25 = 5*5.
35 = 7*5.
40 = 5*2*2*2.
Highest factors of all these numbers is 1400(2*2*2*5*5*7).
So final answer is 3/1400.
H.C.F of numerators,
9 = 3*3.
12 = 3*2*2.
18 = 2*3*3.
21 = 7*3.
Common least factors of these numbers is 3(h.c.f).
L.C.M of denominators,
10 = 2*5.
25 = 5*5.
35 = 7*5.
40 = 5*2*2*2.
Highest factors of all these numbers is 1400(2*2*2*5*5*7).
So final answer is 3/1400.
Rajesh said:
1 decade ago
Can anyone explain, how this method give H.C.F?
Amrit kaur said:
1 decade ago
Any other method to find H.C.F ?
Vani varma said:
1 decade ago
@manasa
5 10 25 35 40
2 2 5 7 8
1 5 7 4
lcm = 5*2*1*5*7*4 = 1400
5 10 25 35 40
2 2 5 7 8
1 5 7 4
lcm = 5*2*1*5*7*4 = 1400
Zafar khan said:
1 decade ago
H.C.F= H.C.F of Numerators/L.C.M of Denominators
L.C.M= L.C.M of Numerators/H.C.F of Denominators
L.C.M= L.C.M of Numerators/H.C.F of Denominators
Keta said:
1 decade ago
Can you please explain in depth. ?
Manasa said:
1 decade ago
How we get 1400 in the lcm part? Please can any one explain ?
Vivek chandra mishra said:
1 decade ago
Here hcf of 9=3*3,12=3*2*2,18=3*3*2,21=3*7
HCF=3
LCM of 10=2*5,25=5*5,35=3*7,40=2*2*2*5
LCM=1400
Required hcf = hcf/lcm
=3/1400
HCF=3
LCM of 10=2*5,25=5*5,35=3*7,40=2*2*2*5
LCM=1400
Required hcf = hcf/lcm
=3/1400
Aparna said:
1 decade ago
Ya, its exactly the right answer.
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