Aptitude - Problems on H.C.F and L.C.M - Discussion

Discussion Forum : Problems on H.C.F and L.C.M - General Questions (Q.No. 29)
29.
The H.C.F. of 9 , 12 , 18 and 21 is:
10 25 35 40
3
5
252
5
3
1400
63
700
Answer: Option
Explanation:
Required H.C.F. = H.C.F. of 9, 12, 18, 21 = 3
L.C.M. of 10, 25, 35, 40 1400
Discussion:
29 comments Page 2 of 3.

Saidaiah said:   7 years ago
The Lcm is 3/2800.

Gopal said:   7 years ago
For the same question instead of hcf if LCM was asked what will be the answer? Please solve it.

Amir said:   9 years ago
If we take LCM collectively, the HCF is 2 and 3, if one by one it's 3. How can we recognise that the HCF should be taken separately?

Amit said:   9 years ago
Answer Should be 3/2800.

Because,
H.C.F of 9, 12, 18, 21 is 3.
L.C.M of 10, 25, 35, 40 is 2800.

So, the answer is 3/2800.

Sanjuu s said:   9 years ago
Simply

Here HCF of 9 =3 * 3, 12 = 3 * 2 * 2, 18 = 3 * 3 * 2, and 21 = 3 * 7.
HCF = 3.

LCM of 10 =2 * 5, 25 = 5* 5, 35 = 3 * 7, 40 = 2* 2 * 2 * 5.
LCM = 1400.

Required HCF = HCF/LCM.
= 3/1400.

Dillip said:   9 years ago
Actually, the answer is showing 3/2800. That's why getting confused. I also got the result 3/1400.

Bhushan said:   1 decade ago
Is this the correct answer?

Mozzima said:   1 decade ago
Why we have taken LCM of denominator?

Anil said:   1 decade ago
Can you please explain shortcut?

Electronics said:   1 decade ago
The concept behind hcf/lcm is that suppose we take 9/10 now there should be a fraction a/b that exactly divides it (9/10) / (a/b) = (9*b) / (10*a) now you take a as hcf of all numbers (numerators only) that will exactly divide 9.

Now for b if you take hcf of denominators it will exactly divide 10 but now there will be a number in denominator of our expression giving us fraction but if we rather take lcm then 10 will go in integral number to divide b and we will get integer.


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