Aptitude - Problems on Ages - Discussion
Discussion Forum : Problems on Ages - Data Sufficiency 1 (Q.No. 1)
Directions to Solve
Each of the questions given below consists of a statement and / or a question and two statements numbered I and II given below it. You have to decide whether the data provided in the statement(s) is / are sufficient to answer the given question. Read the both statements and
- Give answer (A) if the data in Statement I alone are sufficient to answer the question, while the data in Statement II alone are not sufficient to answer the question.
- Give answer (B) if the data in Statement II alone are sufficient to answer the question, while the data in Statement I alone are not sufficient to answer the question.
- Give answer (C) if the data either in Statement I or in Statement II alone are sufficient to answer the question.
- Give answer (D) if the data even in both Statements I and II together are not sufficient to answer the question.
- Give answer(E) if the data in both Statements I and II together are necessary to answer the question.
1.
What is Sonia's present age? | |
I. | Sonia's present age is five times Deepak's present age. |
II. | Five years ago her age was twenty-five times Deepak's age at that time. |
Answer: Option
Explanation:
I. S = 5D  D = |
S | ....(i) |
| 5 |
II. S - 5 = 25 (D - 5) 
S = 25D - 120 ....(ii)
| Using (i) in (ii), we get S = |  |
25 x | S |  |
- 120 |
| 5 |
4S = 120.
S = 30.
Thus, I and II both together give the answer. So, correct answer is (E).
Discussion:
14 comments Page 1 of 2.
Palak said:
1 decade ago
Geeta and deb-in 1st sonia's(S) age is 5 time the deepak(D) present age i.e S=5D OR D=S/5
in 2nd equation,5 years ago her age was 25 times the deepak at that time,i.e we deduce ages for 5 yrs ago i.e -5 or S-5 IS 25(D-5)as deepak age is also reduce by 5 from present age.on solving the equation comes S=25D-120.on putting value of D from first eqnt into 2nd we can get S i.e 30
in 2nd equation,5 years ago her age was 25 times the deepak at that time,i.e we deduce ages for 5 yrs ago i.e -5 or S-5 IS 25(D-5)as deepak age is also reduce by 5 from present age.on solving the equation comes S=25D-120.on putting value of D from first eqnt into 2nd we can get S i.e 30
Amrish said:
9 years ago
According to I st statement.
Let D's age is X year then S's age is 5X year.
According to II.
=> 5 year ago,
S's age was 5X - 5 & D's age was X - 5.
But it say that it 5 yr ago S's age was 25 times of D's age at that time. So,
5X - 5 = 25(X - 5)
20X = 120; X = 6.
Now we can find age of S, D.
S = 5 * 6 = 30yr.
D = 6yr.
So, both statement are necessary.
Let D's age is X year then S's age is 5X year.
According to II.
=> 5 year ago,
S's age was 5X - 5 & D's age was X - 5.
But it say that it 5 yr ago S's age was 25 times of D's age at that time. So,
5X - 5 = 25(X - 5)
20X = 120; X = 6.
Now we can find age of S, D.
S = 5 * 6 = 30yr.
D = 6yr.
So, both statement are necessary.
(1)
A.santhanalakshmi said:
5 years ago
Deepika's present age= x.
Sonia present age=5x.
5x-5=25(x-5),
5x-5=25X-125,
20x-120=0,
x=6.
Sonia's present age = 30.
Sonia present age=5x.
5x-5=25(x-5),
5x-5=25X-125,
20x-120=0,
x=6.
Sonia's present age = 30.
(1)
Priya said:
5 years ago
Sonia's present age =5x, Deepak's present age=x.
Five years ago is past, that is s-5, d-5 formula.
n'times=n*x.
25 times.
Here, s=5D.
D = s/5.
s-5 = 25(D-5).
s-5 = (25 * D) - (25 * 5).
s-5 = 25D-120
D = s/5.
s = (25 * s/5)-120,
4s = 120,
s = 120÷4.
s = 30.
Five years ago is past, that is s-5, d-5 formula.
n'times=n*x.
25 times.
Here, s=5D.
D = s/5.
s-5 = 25(D-5).
s-5 = (25 * D) - (25 * 5).
s-5 = 25D-120
D = s/5.
s = (25 * s/5)-120,
4s = 120,
s = 120÷4.
s = 30.
Balakumar said:
9 years ago
S = 5D.
D = S/5 Eq -> 1.
Then S - 5 = 25(D - 5).
S = 25D - 120 Eq -> 2.
In that Eq 1, D value substitute in Eq 2.
Then S = 25 * (S/5) - 120.
Then 5 IS SUBSTITUTE TO (S & 120).
Then 5S = 25S - 600.
25S - 5S = 600.
20S = 600.
S = 600/20.
S = 30.
D = S/5 Eq -> 1.
Then S - 5 = 25(D - 5).
S = 25D - 120 Eq -> 2.
In that Eq 1, D value substitute in Eq 2.
Then S = 25 * (S/5) - 120.
Then 5 IS SUBSTITUTE TO (S & 120).
Then 5S = 25S - 600.
25S - 5S = 600.
20S = 600.
S = 600/20.
S = 30.
Rajat Jimmy said:
9 years ago
Solution is correct, i.e. 20.
If you related bit 1 and bit 2, then solution is 30.
But in data sufficiency, our main approach is to get solution thru individually bit no. So in this case solution 30 violates.
If you related bit 1 and bit 2, then solution is 30.
But in data sufficiency, our main approach is to get solution thru individually bit no. So in this case solution 30 violates.
Shubham said:
7 years ago
s=d5 then let s value =d5.
then put in (ii) s=25d-120,
d5=25d-120,
120=25d-5d,
120=20d ......then d=6 and s=30.
then put in (ii) s=25d-120,
d5=25d-120,
120=25d-5d,
120=20d ......then d=6 and s=30.
Santosh patil said:
10 years ago
II. S-5 = 25 (D-5) S = 25D - 120......(ii)
25*d = 25d.... & 25*5= 125 ok then 120 is what?
25*d = 25d.... & 25*5= 125 ok then 120 is what?
Deb said:
1 decade ago
I don't understand this method please another method give and help me.
Geetha said:
1 decade ago
I can't understand this.
Can anyone explain this in detail.
Can anyone explain this in detail.
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