Aptitude - Problems on Ages - Discussion
Discussion Forum : Problems on Ages - General Questions (Q.No. 12)
12.
Ayesha's father was 38 years of age when she was born while her mother was 36 years old when her brother four years younger to her was born. What is the difference between the ages of her parents?
Answer: Option
Explanation:
Mother's age when Ayesha's brother was born = 36 years.
Father's age when Ayesha's brother was born = (38 + 4) years = 42 years.
Required difference = (42 - 36) years = 6 years.
Discussion:
44 comments Page 5 of 5.
Chithra said:
5 years ago
Thanks @Palavi.
(3)
M/s Burhaan GHY said:
3 years ago
When the father's age is 38 Aysha's age 0.
When Mother's age is 36 Aysha's age 4.
So that when the father 38 then the mother 32,
So the difference between their parents is 38-32 = 6 years.
When Mother's age is 36 Aysha's age 4.
So that when the father 38 then the mother 32,
So the difference between their parents is 38-32 = 6 years.
(56)
Fahad said:
2 years ago
Ayesha's age = x.
Father's age = 38-x.
Brother's age = x-4.
Mother's age = 36-(x-4).
Parents age difference = (38-x)-(36-(x-4)).
= 38 - x - 36 + x + 4.
= 6.
Father's age = 38-x.
Brother's age = x-4.
Mother's age = 36-(x-4).
Parents age difference = (38-x)-(36-(x-4)).
= 38 - x - 36 + x + 4.
= 6.
(13)
Syed Rasheed said:
3 months ago
Simple,
When Ayesha was born, the father's age is 38.
When his brother 4 years younger than her sister mother's age is 36.
Then 4 years of the father's increasing,
So, 42 - 36,
6 yrs.
When Ayesha was born, the father's age is 38.
When his brother 4 years younger than her sister mother's age is 36.
Then 4 years of the father's increasing,
So, 42 - 36,
6 yrs.
(1)
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers