Aptitude - Problems on Ages - Discussion
Discussion Forum : Problems on Ages - General Questions (Q.No. 3)
3.
A father said to his son, "I was as old as you are at the present at the time of your birth". If the father's age is 38 years now, the son's age five years back was:
Answer: Option
Explanation:
Let the son's present age be x years. Then, (38 - x) = x
2x = 38.
x = 19.
Son's age 5 years back (19 - 5) = 14 years.
Discussion:
100 comments Page 5 of 10.
Maha said:
8 years ago
How did you formed (38-x) =x?
Tej said:
8 years ago
Thanks to all for giving clear explanations.
Tanushree said:
8 years ago
Thanks for the answer.
Thakurdas said:
8 years ago
38-x=x? Can anyone explain this?
Astik thombare said:
6 years ago
0-------------38
38-----------38+38 i.e.2*38.
From above we can conclude that son's age =father's age/2,
son's age =38/2=19,
hence,age of son before 5 years =19-5=14.
Son's age = 14 yrs.
38-----------38+38 i.e.2*38.
From above we can conclude that son's age =father's age/2,
son's age =38/2=19,
hence,age of son before 5 years =19-5=14.
Son's age = 14 yrs.
Kira said:
8 years ago
@Vijay Ananad.
Nicely explain thanks.
Nicely explain thanks.
Adhil said:
8 years ago
38-x=x how can it possible there for 38-15=15 40-2=2 could anyone can explain? please.
Ganesh dadi said:
8 years ago
Let son age X and father age 38.
38(father age)-X (son age ) =X because father's age at the time of sons born (as per question ) =sons age i.e X.
Then 38-X = X.
38(father age)-X (son age ) =X because father's age at the time of sons born (as per question ) =sons age i.e X.
Then 38-X = X.
Shekhawat said:
7 years ago
Father age is Always double of son's age so the answer is 38/2.
Shree said:
7 years ago
@Vijay Anand.
It's a good explanation. Thanks.
It's a good explanation. Thanks.
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