Aptitude - Problems on Ages - Discussion

Discussion Forum : Problems on Ages - General Questions (Q.No. 3)
3.
A father said to his son, "I was as old as you are at the present at the time of your birth". If the father's age is 38 years now, the son's age five years back was:
14 years
19 years
33 years
38 years
Answer: Option
Explanation:

Let the son's present age be x years. Then, (38 - x) = x

2x = 38.

x = 19.

Son's age 5 years back (19 - 5) = 14 years.

Discussion:
99 comments Page 3 of 10.

Prashanth said:   4 years ago
Let present age of son = x.
The present age of the father = 38.
Age of father at the time of his son birth = 38-x.

Father age at the time of his son birth = present age of the son,
38 - x = x,
x = 19
19 - 5 = 14.

How can his son be born at the age of 14? Please anyone explain.
(15)

V.prasanthi said:   1 decade ago
Take three reverse number is descending order. Now reverse the result and add the reversed number with the original. You will get 1089 as the answer.

[A] 765 567+198;198+891+1089 [B] 129 921+891;891+198+1089

[C] 225 522+729;729+927+1089 [D] 139 931+991;991+199+1089

Yuvi said:   7 years ago
Please solve this.

The present age of Geetha is 5 years more than the present age of his brother Mahesh. The present age of their father is twice the sum of their ages. At the time of Mahesh's birth, his father age was 8 times of the age of Geetha.

Find their present ages.
(1)

Anirudh said:   1 decade ago
See, let any variable x be the age of son.

The fathers age is equal to sons present age wen the son was born.

So if you deduct the sons age ie 38-x it shows the faters age when the child was born and eqating to x shows the childs present age so it is a valid result :)

Nanda said:   1 decade ago
@ Kusuma:

"I was as old as you are at the present at the time of your birth".

Means:- Let us assume that son has 10 years now then.

At present father age = 10 years before to son + 10 years after to son.

i.e 20 so son age is half of the father age.

Stella said:   1 decade ago
Friends, I have one doubt.

Father's present age-son's age=father's age at the time of son's birth.

38-x=x.

Here son's age & father's age at the time of son's birth both are assigned to x.

How is it possible? why we can't take two variables?

Imon said:   4 years ago
As we know,

Let 'x' be the present age of the son,

Past:
Son's Age = 0 (just born)
Father's Age = x(present age of son)

Present:
So, after 'x' no. of years, we can say;

x+x = 2x = 38,
x=19.

Answer Required = Five years ago = 19-5=14 years.
(30)

Lavanya said:   1 decade ago
@stella.
It was clearly given in the question that "I was as old as, you are at the present, at the time of your birth". Means son present age= father age at the time of son birth. So, for these two we have to assign same variable.

Bhagyashri said:   1 decade ago
Father's age (38-x).

Son's age x.
Son's age before 5 years (x-5).

Father's age before 5 years (38-x) -5.

(38-x) -5 = (x-5).
33-x = x-5.
33+5 = x+x.
38 = 2x.
x = 19.

Therefore son's age before 5 years (x-5) = (19-5) = 14.

K. Jay Prakash Rao said:   1 decade ago
Let the son's present age be x years. Then, (38 - x) = x. -> why x is subtracted from 38?

2x = 38. -> how 2x = 38 its not mentioned in the question?

x = 19.

Son's age 5 years back (19 - 5) = 14 years.


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