Aptitude - Problems on Ages - Discussion

Discussion Forum : Problems on Ages - General Questions (Q.No. 2)
2.
The sum of ages of 5 children born at the intervals of 3 years each is 50 years. What is the age of the youngest child?
4 years
8 years
10 years
None of these
Answer: Option
Explanation:

Let the ages of children be x, (x + 3), (x + 6), (x + 9) and (x + 12) years.

Then, x + (x + 3) + (x + 6) + (x + 9) + (x + 12) = 50

5x = 20

x = 4.

Age of the youngest child = x = 4 years.

Discussion:
99 comments Page 6 of 10.

Jinju said:   1 decade ago
We can easily understand if the avg is 8 then youngestg should be less thgan 8. Then after we calculate the validity of remaining values.

Stella said:   1 decade ago
Hi cherry, you just see your calculations: x,3x,6x,9x,12x.(wrong)
u have to add x,x+3,x+6,x+9,x+12.(this is the correct format)
now u have to add and get the result ya.

Satheesh said:   1 decade ago
It seems these calculation are merely mathematical wise not logic wise. Whats the relation between X and younger child?

Gkgokulan said:   1 decade ago
Its simple logic frnds 4+7+10+13+16=50.

Then the answer is 4.

Ishu Subham said:   1 decade ago
Let the ages be (x-6), (x-3), (x), (x+3), (x+6).
then sum of ages = 5x
=> 5x = 50
x = 10
youngest = x-6
=4

Hari said:   4 years ago
bro here 50 means?

M.Manimaran said:   5 years ago
Thank you for the formula @Raj.

Ashu said:   5 years ago
Can anyone explain me this again?

Sangeetha said:   1 decade ago
Thank you ishu subham, very simple and good logic.

SIDDHARTHA ROY NANDI said:   1 decade ago
The Problem can be solved using Arithmetic Progression:

S = n/2{2a+(n-1)d}

a = youngest age(We have to calculate this)
n = Total no. of people(5)
d = Difference of Ages in the progression(3)
S = Summation of their ages(50)


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