Aptitude - Problems on Ages - Discussion
Discussion Forum : Problems on Ages - General Questions (Q.No. 2)
2.
The sum of ages of 5 children born at the intervals of 3 years each is 50 years. What is the age of the youngest child?
Answer: Option
Explanation:
Let the ages of children be x, (x + 3), (x + 6), (x + 9) and (x + 12) years.
Then, x + (x + 3) + (x + 6) + (x + 9) + (x + 12) = 50
5x = 20
x = 4.
Age of the youngest child = x = 4 years.
Discussion:
99 comments Page 4 of 10.
Drakshayani said:
1 decade ago
x+ (x+3) + (x+6) + (x+9) + (x+12) =50.
Add all the x is 5x.
And all the numbers is 30.
Then,
5x+30 = 50.
5x = 50 - 30.
5x = 20.
x = 20/5.
x = 4.
So the age of the youngest child is 4.
Add all the x is 5x.
And all the numbers is 30.
Then,
5x+30 = 50.
5x = 50 - 30.
5x = 20.
x = 20/5.
x = 4.
So the age of the youngest child is 4.
Ganesh mudaliyar said:
8 years ago
There is a slight change they should have mention let the youngest child be x.
Then, x + (x + 3) + (x + 6) + (x + 9) + (x + 12) = 50,
5x = 20,
x = 4.
Age of the youngest child = x = 4 years.
Then, x + (x + 3) + (x + 6) + (x + 9) + (x + 12) = 50,
5x = 20,
x = 4.
Age of the youngest child = x = 4 years.
AGS said:
1 decade ago
Let the ages of children be x, (x + 3), (x + 6), (x + 9) and (x + 12) years.
Then, x + (x + 3) + (x + 6) + (x + 9) + (x + 12) = 50
5x = 20
x = 4.
Age of the youngest child = x = 4 years.
Then, x + (x + 3) + (x + 6) + (x + 9) + (x + 12) = 50
5x = 20
x = 4.
Age of the youngest child = x = 4 years.
Nikhil Goyal said:
1 decade ago
Let the ages of children be (x-6), (x - 3), (x), (x + 3) and (x + 6) years.
Then, (x-6)+ (x-3)+ x + (x + 3) + (x + 6) = 50.
5x = 50,
x = 10.
Age of the youngest child = (x-6) = 4 years.
Then, (x-6)+ (x-3)+ x + (x + 3) + (x + 6) = 50.
5x = 50,
x = 10.
Age of the youngest child = (x-6) = 4 years.
Mani Ramani said:
1 decade ago
Hi cherry..
you just add all the X first to get 5X then add numbers to get 30.
Then add 5x+30=50
5X=50-30(shift 30 to right side)
5x=20
X=20/5
X=4
you just add all the X first to get 5X then add numbers to get 30.
Then add 5x+30=50
5X=50-30(shift 30 to right side)
5x=20
X=20/5
X=4
Kumuda said:
1 decade ago
Younger means the person who born at last, then who is the last one, according to problem the person x+12. Submit X value in x+12=16.
Can you please any one clear my doubt ?
Can you please any one clear my doubt ?
Vineshgujjari said:
1 decade ago
First of all, Raj Thank you very much.
But I want to ask you that is this formula will ramain for all the sums of this type i.e. problems of ages.
Please reply me asap.
But I want to ask you that is this formula will ramain for all the sums of this type i.e. problems of ages.
Please reply me asap.
Alisha Mugale said:
3 years ago
Consider A, B, C, D, E are 5 children.
Let the lowest value as 4 for the youngest child.
Start from 4 and add the difference of 3 to each value.
4 + 7+ 10+ 13+ 16 = 50.
Let the lowest value as 4 for the youngest child.
Start from 4 and add the difference of 3 to each value.
4 + 7+ 10+ 13+ 16 = 50.
(37)
Stella said:
1 decade ago
Hi cherry, you just see your calculations: x,3x,6x,9x,12x.(wrong)
u have to add x,x+3,x+6,x+9,x+12.(this is the correct format)
now u have to add and get the result ya.
u have to add x,x+3,x+6,x+9,x+12.(this is the correct format)
now u have to add and get the result ya.
Priyanka said:
1 decade ago
@Sylivia.
Look the options and add 3 to the 1st option and we can find it out i.e., 4+3=7.
Then 7+3=10 actually dat is de middle age: 10+3=13, 13+3=16.
Good luck.
Look the options and add 3 to the 1st option and we can find it out i.e., 4+3=7.
Then 7+3=10 actually dat is de middle age: 10+3=13, 13+3=16.
Good luck.
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