Aptitude - Problems on Ages - Discussion
Discussion Forum : Problems on Ages - General Questions (Q.No. 2)
2.
The sum of ages of 5 children born at the intervals of 3 years each is 50 years. What is the age of the youngest child?
Answer: Option
Explanation:
Let the ages of children be x, (x + 3), (x + 6), (x + 9) and (x + 12) years.
Then, x + (x + 3) + (x + 6) + (x + 9) + (x + 12) = 50
5x = 20
x = 4.
Age of the youngest child = x = 4 years.
Discussion:
102 comments Page 11 of 11.
Kartikey sharma said:
1 month ago
Given:
5 children.
Age gap = 3 years.
Total sum of ages = 50 years.
Assume Youngest Age = x.
Since each child is 3 years older than the previous one:
Ages will be:
x,
x + 3,
x + 6,
x + 9,
x + 12.
From the equation;
Sum = 50.
x(x+3) + (x+6) + (x+9) + (x+12) = 50
5x + (3+6+9+12) = 50.
5x + 30 = 50.
5x = 50 - 30.
5x = 20,
x = 20/5.
x = 4.
Youngest child’s age = 4 years.
5 children.
Age gap = 3 years.
Total sum of ages = 50 years.
Assume Youngest Age = x.
Since each child is 3 years older than the previous one:
Ages will be:
x,
x + 3,
x + 6,
x + 9,
x + 12.
From the equation;
Sum = 50.
x(x+3) + (x+6) + (x+9) + (x+12) = 50
5x + (3+6+9+12) = 50.
5x + 30 = 50.
5x = 50 - 30.
5x = 20,
x = 20/5.
x = 4.
Youngest child’s age = 4 years.
(4)
Vishal Joseph leo said:
2 weeks ago
Let 5 children be born 3 years apart.
x + x + 3x + x + 6 + x + 9 + x + 12 = 50yrs.
5x + 30 = 50yrs,
5x = 50 - 30,
5x = 20.
And x = 4yrs.
x + x + 3x + x + 6 + x + 9 + x + 12 = 50yrs.
5x + 30 = 50yrs,
5x = 50 - 30,
5x = 20.
And x = 4yrs.
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