Aptitude - Problems on Ages - Discussion
Discussion Forum : Problems on Ages - General Questions (Q.No. 2)
2.
The sum of ages of 5 children born at the intervals of 3 years each is 50 years. What is the age of the youngest child?
Answer: Option
Explanation:
Let the ages of children be x, (x + 3), (x + 6), (x + 9) and (x + 12) years.
Then, x + (x + 3) + (x + 6) + (x + 9) + (x + 12) = 50
5x = 20
x = 4.
Age of the youngest child = x = 4 years.
Discussion:
99 comments Page 10 of 10.
Rupesh said:
10 years ago
Can any one, who has in depth knowledge in this can give the age of 3rd person?
Adittya said:
10 years ago
How can we get the age of the middle one or the oldest one?
Tina rajput said:
1 decade ago
The age of the youngest child should be x+12 and not x right?
x is the age of the oldest child.
x is the age of the oldest child.
Suresh.neelikonda said:
1 decade ago
x+(x+3)+(x+6)+(x+9)+(x+12) = 50.
5x+30 = 50.
5x = 20.
x = 4.
5x+30 = 50.
5x = 20.
x = 4.
Nikhil Goyal said:
1 decade ago
Let the ages of children be (x-6), (x - 3), (x), (x + 3) and (x + 6) years.
Then, (x-6)+ (x-3)+ x + (x + 3) + (x + 6) = 50.
5x = 50,
x = 10.
Age of the youngest child = (x-6) = 4 years.
Then, (x-6)+ (x-3)+ x + (x + 3) + (x + 6) = 50.
5x = 50,
x = 10.
Age of the youngest child = (x-6) = 4 years.
AGS said:
1 decade ago
Let the ages of children be x, (x + 3), (x + 6), (x + 9) and (x + 12) years.
Then, x + (x + 3) + (x + 6) + (x + 9) + (x + 12) = 50
5x = 20
x = 4.
Age of the youngest child = x = 4 years.
Then, x + (x + 3) + (x + 6) + (x + 9) + (x + 12) = 50
5x = 20
x = 4.
Age of the youngest child = x = 4 years.
Mahesh said:
1 decade ago
In the question its mentioned that "the intervals of 3 years each is 50 years" it means each child having 50 rit.
Rinshan said:
1 decade ago
4x mean 4 times of the youngest ones age.
Aravind said:
1 decade ago
Here youngest means the smaller (4x), why we took x?
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