Aptitude - Problems on Ages - Discussion

Discussion Forum : Problems on Ages - General Questions (Q.No. 15)
15.
The age of father 10 years ago was thrice the age of his son. Ten years hence, father's age will be twice that of his son. The ratio of their present ages is:
5 : 2
7 : 3
9 : 2
13 : 4
Answer: Option
Explanation:

Let the ages of father and son 10 years ago be 3x and x years respectively.

Then, (3x + 10) + 10 = 2[(x + 10) + 10]

3x + 20 = 2x + 40

x = 20.

Required ratio = (3x + 10) : (x + 10) = 70 : 30 = 7 : 3.

Discussion:
77 comments Page 5 of 8.

Saeed said:   10 years ago
Hi.

Let as consider
Father's age = x.
Son's age = y.

=> 10 year Ago Father's age is x - 10 = 3(y-10) -----> Equation 1.
=> After 10 years Father's age x + 10 = 2(y+10) ------> Equation 2.

Solve 2 equation......
=> x - 10 = 3y - 30.
x - 3y = - 20 --> Equation 3.
=> x - 2y = 10 --> New Equation 4.
=> Substract Equation 3 from Equation 4.
x - 3y = - 20
x - 2y = 10
----------------
- y = - 30.

So, y = 30 --> age of son.

Then put y =30 into any equation.

x - 2(30) = 10
x - 60 = 10.
x = 70 --> age of father.

x = 7.
y = 3.

I hope, this will help you.

Priya said:   9 years ago
In all these questions, we simply assuming son's age as x and father 's age as nx (n=number given).

And why in this question alone we are assuming son's age as x and father 's age as y.

Pleas say the difference.

Bhuban said:   9 years ago
I need an answer to this question and way of solving.

The present age of the father is four times of his son. When will the son be as old as a father now their ages will be 99 find their present ages?

Shiva said:   9 years ago
What is the meaning of fathers age will be twice that of his son?
2(3x + 10 + 10) = (x + 10 + 10).

Why are you taking?
(3x + 10 + 10) = 2((x + 10) + 10).

Please tell me.
(1)

Brindha said:   9 years ago
10 years ago,
Father age is = (3x - 10).
Son age = x.

10 years now.

Father age = 3x - 10 + 10 -------> (2).
Son age is 2 (x + 10) = 2x + 20 -------> (1).

1 = 2.

3x - 10 + 10 = 2x + 20.
x = 20.

Santash Kumar Jena said:   9 years ago
10 years ago:

Son = x - 10,

Father = 3 (x - 10).

10 years hence:

Son = x + 10.

Father = 2 (x + 10).

Equating the age of the father at hence 10 years, so we have to add 20 in the past 10 years.

So,

3 (x - 10) + 20 = 2 (x + 10),

3x - 30 + 20 = 2x + 20,

3x - 2x = 30 - 20 + 20,

X = 30.

Now for present ratio, we will add 10 to past equation.

So,

3 (x - 10) + 10 : x - 10 + 10,

3 (30 - 10) +10 : 30 - 10 + 10,

3 (20) + 10 : 30 = 70 : 30,

7 : 3.
(1)

Lavanya said:   9 years ago
If father's present age is x and how we have to treat x + 3 or 3x in the question?

They mention like son age is 3 times than father age in 3 years hence.

ANGELINE said:   9 years ago
My age 7 years from now is three times my age 15 years ago. What is my present age?

Rajesh said:   9 years ago
@Angeline

Your age is 26.

Jamzeer Narayan Mahato said:   9 years ago
Please solve this.

I am Jamzeer Narayan Mahato.

The present age of the father is four times the age of his son, when the son will be as old as his father now, the sum of their ages will be 99, find their present ages.

Thank in advance.


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