Aptitude - Problems on Ages - Discussion
Discussion Forum : Problems on Ages - General Questions (Q.No. 15)
15.
The age of father 10 years ago was thrice the age of his son. Ten years hence, father's age will be twice that of his son. The ratio of their present ages is:
Answer: Option
Explanation:
Let the ages of father and son 10 years ago be 3x and x years respectively.
Then, (3x + 10) + 10 = 2[(x + 10) + 10]
3x + 20 = 2x + 40
x = 20.
Required ratio = (3x + 10) : (x + 10) = 70 : 30 = 7 : 3.
Discussion:
78 comments Page 5 of 8.
Vani said:
10 years ago
@Arshad.
We can calculate from present age either hence or later and also ago, before, after in any age problems.
We can calculate from present age either hence or later and also ago, before, after in any age problems.
Arshad said:
1 decade ago
Ten years hence means ten years from present age or ten years from past.
Anju said:
1 decade ago
@Javeed:
The age is calculating with respect to the present age. So ten years ago means 3x-10. So the present age will b 3x+10.
Now after ten years 3x+10+10.
The age is calculating with respect to the present age. So ten years ago means 3x-10. So the present age will b 3x+10.
Now after ten years 3x+10+10.
Shubham said:
1 decade ago
Father's age is twice of his son's age. 8 years ago. He was thrice as old as his son. So what will be d son's age at present.
Javeed said:
1 decade ago
10 years ago means 3x - 10. But how it become 3x + 10?
Lakshmi said:
1 decade ago
What is the meaning of fathers age will be twice that of his son.
2(3x+10+10) = (x+10+10).
Why are you taking?
(3x+10+10) = 2((x+10)+10).
Please tell me.
2(3x+10+10) = (x+10+10).
Why are you taking?
(3x+10+10) = 2((x+10)+10).
Please tell me.
EncodeMaster said:
1 decade ago
Let Father = F and Son = S.
10 Years Ago:
F-10 = 3(S-10).
F = 3S-20 ------ (i).
10 year hence:
F+10 = 2(S+10) ------ (ii).
Replace (i) in (ii).
3S-20+10 = 2S+20.
3S-10 = 2S+20.
S = 30 <----- Son's Age.
Again using (i).
F = 3(30)-20.
F = 70.
So Ratio is 70:30 ----> 7:3.
10 Years Ago:
F-10 = 3(S-10).
F = 3S-20 ------ (i).
10 year hence:
F+10 = 2(S+10) ------ (ii).
Replace (i) in (ii).
3S-20+10 = 2S+20.
3S-10 = 2S+20.
S = 30 <----- Son's Age.
Again using (i).
F = 3(30)-20.
F = 70.
So Ratio is 70:30 ----> 7:3.
Neha gupta said:
1 decade ago
After 10 years from the present > Ankur.
Ankur said:
1 decade ago
Whats meaning of 10 years hence?
Vamsee menda said:
1 decade ago
Let the ages of father and son 10 years ago be 3x and x years respectively.
Then, (3x + 10) + 10 = 2[(x + 10) + 10].
3x + 20 = 2x + 40.
x = 20.
Required ratio = (3x + 10) : (x + 10) = 70 : 30 = 7 : 3.
Then, (3x + 10) + 10 = 2[(x + 10) + 10].
3x + 20 = 2x + 40.
x = 20.
Required ratio = (3x + 10) : (x + 10) = 70 : 30 = 7 : 3.
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