Aptitude - Probability - Discussion
Discussion Forum : Probability - General Questions (Q.No. 10)
10.
Two dice are tossed. The probability that the total score is a prime number is:
Answer: Option
Explanation:
Clearly, n(S) = (6 x 6) = 36.
Let E = Event that the sum is a prime number.
Then E | = { (1, 1), (1, 2), (1, 4), (1, 6), (2, 1), (2, 3), (2, 5), (3, 2), (3, 4), (4, 1), (4, 3), (5, 2), (5, 6), (6, 1), (6, 5) } |
n(E) = 15.
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n(E) | = | 15 | = | 5 | . |
n(S) | 36 | 12 |
Discussion:
64 comments Page 2 of 7.
Shikha Patel said:
9 years ago
Thanks @Azly.
By using axis method, we can easily solve the question like this.
By using axis method, we can easily solve the question like this.
Kiran said:
9 years ago
You are considering (1, 1) is a prime set and why not you consider (2, 2), (3, 3), (5, 5) as a prime set?
Nilesh Patil said:
9 years ago
(1,1), (2,1), (2,3), (3,2), (4,1), (1,4), (4,3), (3,4), (5,2), (2,5), (6,1), (1,6), (6,3), (3,6), (6,5),(5,6)
If(1,1) is considered then n(E) becomes 16 then, what's wrong in above?
If(1,1) is considered then n(E) becomes 16 then, what's wrong in above?
Lionel said:
9 years ago
Assume that two independent random samples of size 100 each is taken from a population that has a variance of 36. What is the probability that the difference in the sample means is more than 2?
Please give me the solution.
Please give me the solution.
Tahir amin said:
9 years ago
Please, Solve anyone this question. A committee of 3 is to be selected from a group of 5 girls and 3 boys. What is the probability that two boys are selected?
Sowmya said:
9 years ago
Is total score nothing but the sum?
Karma said:
8 years ago
Here, I used nCr. But its not working, why?
Can anyone explain me.
Can anyone explain me.
Azly said:
9 years ago
If we draw this in a cartesian plan we can easily find the answer. Take d axis and Y axis. Number from 1 to 6 in each axis. The find the sum of the numbers using plan.
Supriya said:
8 years ago
Can anyone explain the simplest method to find numarator?
Durba said:
7 years ago
The sum of (1, 4) (1, 6) is not prime.
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