Aptitude - Probability - Discussion
Discussion Forum : Probability - General Questions (Q.No. 2)
2.
A bag contains 2 red, 3 green and 2 blue balls. Two balls are drawn at random. What is the probability that none of the balls drawn is blue?
Answer: Option
Explanation:
Total number of balls = (2 + 3 + 2) = 7.
Let S be the sample space.
Then, n(S) | = Number of ways of drawing 2 balls out of 7 | |||
= 7C2 ` | ||||
|
||||
= 21. |
Let E = Event of drawing 2 balls, none of which is blue.
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= Number of ways of drawing 2 balls out of (2 + 3) balls. | |||
= 5C2 | ||||
|
||||
= 10. |
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n(E) | = | 10 | . |
n(S) | 21 |
Discussion:
116 comments Page 8 of 12.
Priya said:
5 months ago
(2c0 3c1 + 2c1 3c1 + 2c2 3c0)/7c2.
Which is equal to (3+6+1)/21. = 10/21.
Which is equal to (3+6+1)/21. = 10/21.
Bhavna said:
1 decade ago
I didn't understand the method which sagar did? can anybody make it clear!
Ahmed said:
7 years ago
Simply, find the probability of getting 2 balls blue then subtract from 1.
Stephen said:
1 decade ago
Is there an easier way of doing these type of probability word problems?
Dileep said:
1 decade ago
The way akash did is exact. It takes into account all the probabilities
Laura said:
8 years ago
How 7x6?
where did you get the 6 from?
Please explain it in detail.
where did you get the 6 from?
Please explain it in detail.
Manjunath said:
1 decade ago
In the same question what is the probability of taking 2 blue balls?
PRASHANT SINHA said:
1 decade ago
In the same question what is the probability of taking 2 blue balls?
Shivam said:
1 decade ago
Why are we taking combination and not permutation in this question?
Saurabh said:
1 decade ago
This is the the simplest method to find the Probablity...........
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