Aptitude - Probability - Discussion

Discussion Forum : Probability - General Questions (Q.No. 2)
2.
A bag contains 2 red, 3 green and 2 blue balls. Two balls are drawn at random. What is the probability that none of the balls drawn is blue?
10
21
11
21
2
7
5
7
Answer: Option
Explanation:

Total number of balls = (2 + 3 + 2) = 7.

Let S be the sample space.

Then, n(S) = Number of ways of drawing 2 balls out of 7
= 7C2 `
= (7 x 6)
(2 x 1)
= 21.

Let E = Event of drawing 2 balls, none of which is blue.

n(E) = Number of ways of drawing 2 balls out of (2 + 3) balls.
= 5C2
= (5 x 4)
(2 x 1)
= 10.

P(E) = n(E) = 10 .
n(S) 21

Discussion:
116 comments Page 8 of 12.

Priya said:   5 months ago
(2c0 3c1 + 2c1 3c1 + 2c2 3c0)/7c2.
Which is equal to (3+6+1)/21. = 10/21.

Bhavna said:   1 decade ago
I didn't understand the method which sagar did? can anybody make it clear!

Ahmed said:   7 years ago
Simply, find the probability of getting 2 balls blue then subtract from 1.

Stephen said:   1 decade ago
Is there an easier way of doing these type of probability word problems?

Dileep said:   1 decade ago
The way akash did is exact. It takes into account all the probabilities

Laura said:   8 years ago
How 7x6?

where did you get the 6 from?

Please explain it in detail.

Manjunath said:   1 decade ago
In the same question what is the probability of taking 2 blue balls?

PRASHANT SINHA said:   1 decade ago
In the same question what is the probability of taking 2 blue balls?

Shivam said:   1 decade ago
Why are we taking combination and not permutation in this question?

Saurabh said:   1 decade ago
This is the the simplest method to find the Probablity...........


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