Aptitude - Probability - Discussion

Discussion Forum : Probability - General Questions (Q.No. 2)
2.
A bag contains 2 red, 3 green and 2 blue balls. Two balls are drawn at random. What is the probability that none of the balls drawn is blue?
10
21
11
21
2
7
5
7
Answer: Option
Explanation:

Total number of balls = (2 + 3 + 2) = 7.

Let S be the sample space.

Then, n(S) = Number of ways of drawing 2 balls out of 7
= 7C2 `
= (7 x 6)
(2 x 1)
= 21.

Let E = Event of drawing 2 balls, none of which is blue.

n(E) = Number of ways of drawing 2 balls out of (2 + 3) balls.
= 5C2
= (5 x 4)
(2 x 1)
= 10.

P(E) = n(E) = 10 .
n(S) 21

Discussion:
116 comments Page 7 of 12.

Sathish kumar said:   1 decade ago
Total 7 balls.

Blue 2 balls.

So none of blue is 5 balls : 5c2/7c2.

(5x4/2x1)/(7x6/2x1) = 10/21 answer.

Sundry said:   1 decade ago
From the explanation, where did 6 come from? why did you multiply 7 by 6? I did not understand that one.

Aarthi said:   2 decades ago
Can we do this n different method? finding the possibility that both are blue and finally ans-1.

Neha said:   1 decade ago
What is 3c2, 2c2 etc? could anyone please explain this whole sum according to a class 7 student.

Ritu verma said:   7 years ago
Prob of 1st ball not blue * prob of 2nd ball not blue.

= (5/7)*(4/6),
= 20/42,
= 10/21.

Sarah said:   1 decade ago
The formula for ncr = n!/(n-r)!*r! if you submit values in this you can get the answer.

Aman said:   8 years ago
@Jaani.

What is the probability of picking 2 blue ball then what is the probability?

Faffy said:   9 years ago
What if we use the tree diagrams because the way you answer is kindly complicated.

Gufran said:   5 years ago
(2R+3G)c2/7c2.
5c2/7c2.
5 * 2/2/7 * 6/2.
(20/2)/(42/2).
10/21 is the final answer
(1)

Nagen said:   1 decade ago
Whether sum of probability of 1 blue plus 2 blue is not opposite of none blue.


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