Aptitude - Probability - Discussion

Discussion Forum : Probability - General Questions (Q.No. 2)
2.
A bag contains 2 red, 3 green and 2 blue balls. Two balls are drawn at random. What is the probability that none of the balls drawn is blue?
10
21
11
21
2
7
5
7
Answer: Option
Explanation:

Total number of balls = (2 + 3 + 2) = 7.

Let S be the sample space.

Then, n(S) = Number of ways of drawing 2 balls out of 7
= 7C2 `
= (7 x 6)
(2 x 1)
= 21.

Let E = Event of drawing 2 balls, none of which is blue.

n(E) = Number of ways of drawing 2 balls out of (2 + 3) balls.
= 5C2
= (5 x 4)
(2 x 1)
= 10.

P(E) = n(E) = 10 .
n(S) 21

Discussion:
116 comments Page 11 of 12.

Pragya said:   7 years ago
C2 stands for what? Please explain me.

Malik Ahamed said:   1 year ago
Where did 6 came from? Please explain.
(3)

Soundar said:   2 decades ago
Its a correct answer and short way.

Jay said:   1 decade ago
(7 x 6)
(2 x 1)

Please explan it.

Navcool said:   1 decade ago
Is it with or without replacement?

Summi said:   6 years ago
How come 7*6/2*1? please clear me.

Kenneth said:   10 years ago
Please clear me on how 6 come in?

Suyash said:   8 years ago
Simply, say 5/7 * 4/6.
= 10/21.

Arnika said:   7 years ago
What is C and S please explain?

HEMALATHA said:   6 years ago
@Pranav.

The answer is 62.


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