Aptitude - Probability - Discussion
Discussion Forum : Probability - General Questions (Q.No. 2)
2.
A bag contains 2 red, 3 green and 2 blue balls. Two balls are drawn at random. What is the probability that none of the balls drawn is blue?
Answer: Option
Explanation:
Total number of balls = (2 + 3 + 2) = 7.
Let S be the sample space.
| Then, n(S) | = Number of ways of drawing 2 balls out of 7 | |||
| = 7C2 ` | ||||
|
||||
| = 21. |
Let E = Event of drawing 2 balls, none of which is blue.
 n(E) |
= Number of ways of drawing 2 balls out of (2 + 3) balls. | |||
| = 5C2 | ||||
|
||||
| = 10. |
| P(E) = |
n(E) | = | 10 | . |
| n(S) | 21 |
Discussion:
116 comments Page 10 of 12.
Supriya said:
1 decade ago
How the (7*6)(2*1) has come?
Please clear my concept.
Please clear my concept.
Itachi said:
1 decade ago
Show the answer using conditional probability please!
Burhan said:
9 years ago
Could anybody tell me what is that c means in 7c2?
Riafat Hussain said:
1 year ago
1st ball = 5/7.
2nd ball = 4/6.
5/7 * 4/6 = 10/21.
2nd ball = 4/6.
5/7 * 4/6 = 10/21.
(61)
NAMRA shah said:
9 years ago
Not understanding, please Explain me this method.
Tejeshwari said:
3 years ago
5/7 is it right?
Anyone can explain it, please.
Anyone can explain it, please.
(9)
Naseem Ullah Khan said:
5 years ago
Simple explanation, well done, thanks @Krish.
(2)
Sneha said:
1 year ago
Can anyone explain this in the short method?
(8)
Rose were said:
1 decade ago
Why are you multiplying by 6 and by 4?
Chi said:
1 decade ago
What is the formula for this question?
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