Aptitude - Probability - Discussion

Discussion Forum : Probability - General Questions (Q.No. 13)
13.
Two cards are drawn together from a pack of 52 cards. The probability that one is a spade and one is a heart, is:
3
20
29
34
47
100
13
102
Answer: Option
Explanation:

Let S be the sample space.

Then, n(S) = 52C2 = (52 x 51) = 1326.
(2 x 1)

Let E = event of getting 1 spade and 1 heart.

n(E) = number of ways of choosing 1 spade out of 13 and 1 heart out of 13
= (13C1 x 13C1)
= (13 x 13)
= 169.

P(E) = n(E) = 169 = 13 .
n(S) 1326 102

Discussion:
42 comments Page 4 of 5.

Neeta said:   1 decade ago
Can anybody explain me how to solve 52C2 ? or such other examples like 7C2, 13C1 etc.

Irfan said:   1 decade ago
52C2 = 52/2*51/1 i.e. 1326 Answer.

or

nCr = n!/(r!)(n - r)!

Kavitha said:   1 decade ago
Why can't it be (13C1 + 13C1) I am getting confused where 2 multiply and where 2 add can any one help me.

Khetesh said:   1 decade ago
Actually answer 13/102 is correct.

We draw 2 card:

Possibility of one heart and one spade = (possibility of first spade and second heart) + (possibility of first heart and second spade).

= (13/52)*(13/51) + (13/52)*(13/51).

= 13*13*2/52*51.

= 13/102.

Jayalekshshmi s said:   1 decade ago
Number of hearts and spades in a deck of cards is 26. Am I right?

Vinay said:   1 decade ago
Probability of A and B = P(a) * P(b).
Probability of A or B = P(a) + P(b).

So, 13/204 is correct, no ?

Sulagna said:   1 decade ago
If we are supposed to multiply 13/204 into 2, because w are considering 2 events= 1st spade 2nd heart and 2nd heart, 1st spade, then in the coloured marbles question, why don't we apply the same logic?

Dhruvil said:   1 decade ago
Probability = (13+13)/(52*51) = 26/(52*51) = 1/102.

As there are 13 spade cards and 13 heart cards in each pack of 52 cards.

Priya said:   1 decade ago
Why can't it be 26C2/52C2?

Shekhar said:   1 decade ago
Why can't this be done ?

26P2/52C2 ?

Can anyone please give me a proper explanation.


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