Aptitude - Probability - Discussion

Discussion Forum : Probability - General Questions (Q.No. 13)
13.
Two cards are drawn together from a pack of 52 cards. The probability that one is a spade and one is a heart, is:
3
20
29
34
47
100
13
102
Answer: Option
Explanation:

Let S be the sample space.

Then, n(S) = 52C2 = (52 x 51) = 1326.
(2 x 1)

Let E = event of getting 1 spade and 1 heart.

n(E) = number of ways of choosing 1 spade out of 13 and 1 heart out of 13
= (13C1 x 13C1)
= (13 x 13)
= 169.

P(E) = n(E) = 169 = 13 .
n(S) 1326 102

Discussion:
42 comments Page 4 of 5.

Karim said:   1 decade ago
@Ali, your answer is correct.

The answer should in fact be 13/204 and not 13/102.

You have 13/52 for the first card and for the second it's 13/51.

Multiple together you get 13/204.
(1)

Ali said:   1 decade ago
But 13/52 * 13/51 is not equal to 13/102, but rather 13/204.

Irfan said:   1 decade ago
52C2 = 52/2*51/1 i.e. 1326 Answer.

or

nCr = n!/(r!)(n - r)!

Neeta said:   1 decade ago
Can anybody explain me how to solve 52C2 ? or such other examples like 7C2, 13C1 etc.

Amol said:   1 decade ago
Thanks Probability

Santosh said:   1 decade ago
Here actually we discussed earlier as both are same combination we add other wise multiply. So clarify that doubt. I understood this problem but add and multiply explain.

Xyz said:   1 decade ago
@ kavita:
in case of "AND" we have to "multiply"
& in case of "OR" we have to "Add"

Swetha said:   1 decade ago
@kavitha.

In this question, we have to find propability for taking 2 cards one is spade and another one is heart. If and comes, we should multiply likewise if or is given, then we should add.

Mdk said:   1 decade ago
Thanks parikshit.

Probablity said:   1 decade ago
1st card is a spade = 13/52 AND
2nd card is a heart = 13/51

therefore 13/52 x 13/51 ... (1)

OR

1st card is a heart = 13/52 AND
2nd card is a spade = 13/51

therefore 13/52 x 13/51 ... (2)

Adding 1 & 2 we get 13/102


Post your comments here:

Your comments will be displayed after verification.