Aptitude - Probability - Discussion

Discussion Forum : Probability - General Questions (Q.No. 13)
13.
Two cards are drawn together from a pack of 52 cards. The probability that one is a spade and one is a heart, is:
3
20
29
34
47
100
13
102
Answer: Option
Explanation:

Let S be the sample space.

Then, n(S) = 52C2 = (52 x 51) = 1326.
(2 x 1)

Let E = event of getting 1 spade and 1 heart.

n(E) = number of ways of choosing 1 spade out of 13 and 1 heart out of 13
= (13C1 x 13C1)
= (13 x 13)
= 169.

P(E) = n(E) = 169 = 13 .
n(S) 1326 102

Discussion:
42 comments Page 3 of 5.

Farheen said:   9 years ago
P(c) = n(c)/n(s).
= 1/52 a king of hearts . Is it true?

Naj said:   10 years ago
Why do we have to divide (52 x 51) by 2?

Anamika said:   1 decade ago
The probability of getting spades and hearts why not 26C52+26C51. Because spades and hearts may be from red and black colours of cards.

Shekhar said:   1 decade ago
Why can't this be done ?

26P2/52C2 ?

Can anyone please give me a proper explanation.

Priya said:   1 decade ago
Why can't it be 26C2/52C2?

Dhruvil said:   1 decade ago
Probability = (13+13)/(52*51) = 26/(52*51) = 1/102.

As there are 13 spade cards and 13 heart cards in each pack of 52 cards.

Sulagna said:   1 decade ago
If we are supposed to multiply 13/204 into 2, because w are considering 2 events= 1st spade 2nd heart and 2nd heart, 1st spade, then in the coloured marbles question, why don't we apply the same logic?

Vinay said:   1 decade ago
Probability of A and B = P(a) * P(b).
Probability of A or B = P(a) + P(b).

So, 13/204 is correct, no ?

Jayalekshshmi s said:   1 decade ago
Number of hearts and spades in a deck of cards is 26. Am I right?

Khetesh said:   1 decade ago
Actually answer 13/102 is correct.

We draw 2 card:

Possibility of one heart and one spade = (possibility of first spade and second heart) + (possibility of first heart and second spade).

= (13/52)*(13/51) + (13/52)*(13/51).

= 13*13*2/52*51.

= 13/102.


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