Aptitude - Probability - Discussion
Discussion Forum : Probability - General Questions (Q.No. 13)
13.
Two cards are drawn together from a pack of 52 cards. The probability that one is a spade and one is a heart, is:
Answer: Option
Explanation:
Let S be the sample space.
Then, n(S) = 52C2 = | (52 x 51) | = 1326. |
(2 x 1) |
Let E = event of getting 1 spade and 1 heart.
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= number of ways of choosing 1 spade out of 13 and 1 heart out of 13 |
= (13C1 x 13C1) | |
= (13 x 13) | |
= 169. |
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n(E) | = | 169 | = | 13 | . |
n(S) | 1326 | 102 |
Discussion:
42 comments Page 3 of 5.
Kavitha said:
1 decade ago
Why can't it be (13C1 + 13C1) I am getting confused where 2 multiply and where 2 add can any one help me.
Vinay said:
1 decade ago
Probability of A and B = P(a) * P(b).
Probability of A or B = P(a) + P(b).
So, 13/204 is correct, no ?
Probability of A or B = P(a) + P(b).
So, 13/204 is correct, no ?
Shekhar said:
1 decade ago
Why can't this be done ?
26P2/52C2 ?
Can anyone please give me a proper explanation.
26P2/52C2 ?
Can anyone please give me a proper explanation.
Neeta said:
1 decade ago
Can anybody explain me how to solve 52C2 ? or such other examples like 7C2, 13C1 etc.
Sofiya said:
4 years ago
Why can't it be 13c2*13c2/52?
Can anyone give me a proper explanation?
Can anyone give me a proper explanation?
Jayalekshshmi s said:
1 decade ago
Number of hearts and spades in a deck of cards is 26. Am I right?
Qaisara said:
8 years ago
I am unable to understand about 13. So anyone please explain me.
Uchenna said:
8 years ago
Does it mean that every pack must have 13 spade and 13 hearts?
Irfan said:
1 decade ago
52C2 = 52/2*51/1 i.e. 1326 Answer.
or
nCr = n!/(r!)(n - r)!
or
nCr = n!/(r!)(n - r)!
Ali said:
1 decade ago
But 13/52 * 13/51 is not equal to 13/102, but rather 13/204.
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