Aptitude - Probability - Discussion
Discussion Forum : Probability - General Questions (Q.No. 13)
13.
Two cards are drawn together from a pack of 52 cards. The probability that one is a spade and one is a heart, is:
Answer: Option
Explanation:
Let S be the sample space.
| Then, n(S) = 52C2 = | (52 x 51) | = 1326. |
| (2 x 1) |
Let E = event of getting 1 spade and 1 heart.
 n(E) |
= number of ways of choosing 1 spade out of 13 and 1 heart out of 13 |
| = (13C1 x 13C1) | |
| = (13 x 13) | |
| = 169. |
| P(E) = |
n(E) | = | 169 | = | 13 | . |
| n(S) | 1326 | 102 |
Discussion:
42 comments Page 2 of 5.
ARNAV said:
4 years ago
The answer over here is wrong.
As it is mentioned we should be adding.
(13c1+13c1) / 52c2.
=1/51=> is the correct answer.
As it is mentioned we should be adding.
(13c1+13c1) / 52c2.
=1/51=> is the correct answer.
Farheen said:
9 years ago
P(c) = n(c)/n(s).
= 1/52 a king of hearts . Is it true?
= 1/52 a king of hearts . Is it true?
Sasi said:
7 years ago
Why not adding two type of cards as 26c2?
Vedant said:
7 years ago
It is very helpful explanation, Thanks @Khetesh.
Rishit said:
7 years ago
@Ali and @Karim.
Here 2 cards are drawn TOGETHER. Which is why the 52c2. Your answer is correct for a scenario if the question was first drawn is club and second drawn is heart or vice versa.
Here 2 cards are drawn TOGETHER. Which is why the 52c2. Your answer is correct for a scenario if the question was first drawn is club and second drawn is heart or vice versa.
Qaisara said:
8 years ago
I am unable to understand about 13. So anyone please explain me.
VANAMALA SRINIVAS said:
8 years ago
No, the correct answer is 3/102.
Uchenna said:
8 years ago
Does it mean that every pack must have 13 spade and 13 hearts?
Ashish said:
9 years ago
Thanks @Vineet.
Rangesh said:
4 years ago
@ALL.
Total pack of cards 52.
One card from spade so spade contains 13cards.
One card from the heart so spade contains 13cards.
Use C method.
One card from spade and (*) one card from heart =13C1 * 13C1.
Total cards to be picked =2, so 52C2= (52*51)÷(1*2).
Now simplify
(13C1*13C1)÷(52*51 /1*2).
If we simply the common terms we get.
13/2*51 =13/102.
By simplifying, we will get the answer.
Total pack of cards 52.
One card from spade so spade contains 13cards.
One card from the heart so spade contains 13cards.
Use C method.
One card from spade and (*) one card from heart =13C1 * 13C1.
Total cards to be picked =2, so 52C2= (52*51)÷(1*2).
Now simplify
(13C1*13C1)÷(52*51 /1*2).
If we simply the common terms we get.
13/2*51 =13/102.
By simplifying, we will get the answer.
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