Aptitude - Probability - Discussion
Discussion Forum : Probability - General Questions (Q.No. 9)
9.
From a pack of 52 cards, two cards are drawn together at random. What is the probability of both the cards being kings?
Answer: Option
Explanation:
Let S be the sample space.
| Then, n(S) = 52C2 = | (52 x 51) | = 1326. |
| (2 x 1) |
Let E = event of getting 2 kings out of 4.
 n(E) = 4C2 = |
(4 x 3) | = 6. |
| (2 x 1) |
| P(E) = |
n(E) | = | 6 | = | 1 | . |
| n(S) | 1326 | 221 |
Discussion:
32 comments Page 2 of 4.
Gangadhar said:
7 years ago
There are 4 Kings so;
(4/52)
When you are taking 2nd card the total number of cards you have are 51 and out of 51 you have 3kings do (3/51).
Finally, (4/52) * (3/51) = (1/221).
(4/52)
When you are taking 2nd card the total number of cards you have are 51 and out of 51 you have 3kings do (3/51).
Finally, (4/52) * (3/51) = (1/221).
(6)
Pinky said:
2 years ago
Here they asked about the probability of 2 kings out of 52 cards.
No.of kings in a deck of cards = 4
P(E)= no of favourable outcomes/no.of possible outcomes.
So, 4/52 = 1/13.
No.of kings in a deck of cards = 4
P(E)= no of favourable outcomes/no.of possible outcomes.
So, 4/52 = 1/13.
(4)
Rahul said:
1 decade ago
Because in apack of cards 4 kings are there. So selecting 2 kings out of 4 is 4c2. Generally in apack of cards the 4 suits are aces, kings, queens, jacks.
Swetha said:
1 decade ago
@Arun Sharma
There are 13 types of cards.,but the question asked is both are kings. We have only 4 kings. Therefore we must take 2 kings out of 4 kings.
There are 13 types of cards.,but the question asked is both are kings. We have only 4 kings. Therefore we must take 2 kings out of 4 kings.
Dhruvil said:
1 decade ago
Probability = (4*3/52*51) = (3/661).
As there are 4 kings in a single pack of cards and 2 cards are selected from 52 cards so the answer is (3/661).
As there are 4 kings in a single pack of cards and 2 cards are selected from 52 cards so the answer is (3/661).
Rohit said:
1 decade ago
4/52 is the chance of getting 1st King.
3/51 is the chance of getting 2nd King.
So, probability of getting 2 kings is:
4/52 * 3/51 = 1/221.
3/51 is the chance of getting 2nd King.
So, probability of getting 2 kings is:
4/52 * 3/51 = 1/221.
Shreya said:
6 years ago
Here the question is the probability of getting kings only that is getting the same combination.
Can we use (4/52) + (3/51)? Please tell me.
Can we use (4/52) + (3/51)? Please tell me.
(3)
Gaurav Garg said:
1 decade ago
@Santhu.
We are not selecting cards from only 4 kings, we are selecting them from all 52 cards And next time from 51 cards.
We are not selecting cards from only 4 kings, we are selecting them from all 52 cards And next time from 51 cards.
Purva said:
3 years ago
Two cards are drawn together dependent event.
P(A and B) = P(A) * P(B/A).
= 4/52 * 3/51 = 1/221.
P(A and B) = P(A) * P(B/A).
= 4/52 * 3/51 = 1/221.
(7)
Srini said:
8 years ago
The probability of 2 out of 4 is 1/2.
And the sample space is 2 /52.
Is this correct or wrong can anyone explain?
And the sample space is 2 /52.
Is this correct or wrong can anyone explain?
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers