Aptitude - Probability - Discussion

Discussion Forum : Probability - General Questions (Q.No. 1)
1.
Tickets numbered 1 to 20 are mixed up and then a ticket is drawn at random. What is the probability that the ticket drawn has a number which is a multiple of 3 or 5?
1
2
2
5
8
15
9
20
Answer: Option
Explanation:

Here, S = {1, 2, 3, 4, ...., 19, 20}.

Let E = event of getting a multiple of 3 or 5 = {3, 6 , 9, 12, 15, 18, 5, 10, 20}.

P(E) = n(E) = 9 .
n(S) 20

Discussion:
107 comments Page 6 of 11.

Sagar Valecha Soni said:   1 decade ago
Ya 9/20 is correct I am agree from this answer.

Garima said:   10 years ago
According to me the answer should be 1/2.

Multiples of 3 and 5. (1, 3, 5, 6, 9, 10, 12, 15, 18, 20).

Please let me know where am I wrong?

Divya said:   10 years ago
How to cal multiple of larger number?

Can any one give a answer for this?

Ex: Same question number is 1-300.

Samuel said:   10 years ago
@Divya.

Factorize or divide it.

Rutu said:   9 years ago
Why s=20 selected? please give me answer.

Mahesh said:   9 years ago
What's, and what is e please explain?

Shailendra rathore said:   9 years ago
9/20 is the right answer, and thanks for explaining the answer in different ways.

Saurav said:   9 years ago
As both the events A and B are independent and non-mutually exclusive we can use the following formula:.

P (A or B) = P (A) + P (B) - P (A and B).

= 6/20 + 4/20 - (6/20 * 4/20) [probability intersection rule for dependent events].

= 10/20 - 3/50.

= 50 - 6/100.

= 44/100 = 11/25. But this answer is not in the option.

Rani said:   9 years ago
Where this 5 gone in the event?

Mani said:   9 years ago
Where this 6 gone in the event?


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