Aptitude - Probability - Discussion

Discussion Forum : Probability - General Questions (Q.No. 1)
1.
Tickets numbered 1 to 20 are mixed up and then a ticket is drawn at random. What is the probability that the ticket drawn has a number which is a multiple of 3 or 5?
1
2
2
5
8
15
9
20
Answer: Option
Explanation:

Here, S = {1, 2, 3, 4, ...., 19, 20}.

Let E = event of getting a multiple of 3 or 5 = {3, 6 , 9, 12, 15, 18, 5, 10, 20}.

P(E) = n(E) = 9 .
n(S) 20

Discussion:
107 comments Page 5 of 11.

Prawesh Pradhan said:   9 years ago
From 1 to 20, numbers which are divisible by 3 are 3, 6, 9, 12, 15 & 18 -> total 6.
Numbers divisible by 5 are 5, 10, 15, 20 total 4.

So, 6 + 4 = 10. But 15 is counted twice. Therefore 10 - 1= 9. Result is 9/20.

Prawesh Pradhan said:   9 years ago
P(A) + P(B) - P(A and B).
6 + 4 - 1 = 9.
P(E) = n(E)/n(S).
P(E) = 9/20.

Deva Bala said:   9 years ago
The option d) 9/20 is the correct answer.

Anonymous said:   9 years ago
The correct answer is 9/20.

Dabir Masood said:   9 years ago
Yes I too agree that 1/2 is the correct answer for this question.
(1)

Gad said:   9 years ago
A = multiple of 3 (3, 6, 9, 12, 15, 18).
Possible outcome = 6.

B = multiple of 5 (5, 10, 15, 20).
Possible outcome = 4.

Therefore, P (A or B) = P (A) + P (B).

6/20 + 4/20 = 10/20 = 1/2.

Nicole said:   9 years ago
I'm confused, on how thy got D as an answer?

Mani said:   9 years ago
Where this 6 gone in the event?

Rani said:   9 years ago
Where this 5 gone in the event?

Saurav said:   9 years ago
As both the events A and B are independent and non-mutually exclusive we can use the following formula:.

P (A or B) = P (A) + P (B) - P (A and B).

= 6/20 + 4/20 - (6/20 * 4/20) [probability intersection rule for dependent events].

= 10/20 - 3/50.

= 50 - 6/100.

= 44/100 = 11/25. But this answer is not in the option.


Post your comments here:

Your comments will be displayed after verification.