Aptitude - Probability - Discussion

@Uday,

15 is repeated.
And 5 is missing.
Anyway, the answer is correct.

Nice solution, Thanks, everyone.

@Shraddha.

5 is also considered so that we get probability 9/20. If 5 is not considered we can't get 9/20.

Here, the total ticket is 20 we gonna take 1 from that 20 tickets it can be multiple of 3 or 5
so,

5C1 + 3C1/20C1 = 5+3/20 = 8/20.

= 2/5 is correct.

Here, S = {1, 2, 3, 4, ...., 19, 20}.

Let E = event of getting a multiple of 3 or 5 = {3, 6 , 9, 12, 15, 18, 5, 10, 15, 20}.

P(E) = 1/2.

Is this correct? Please give your thoughts on this.

Sundar & Manju thought wrong because 15 already be consider.

So ans will be 9/20.

As per Addition Rule of Probability, we can have two set of events - Mutually Exclusive & Non-Mutually Exclusive..where Mutually Exclusive events don't occur simultaneously or together and reverse logic with Non-Mutually Exclusive events.

Having this theorem told in above para, now i come to the context:

We have 2 events,

Event A: Ticket picked is multiple of 3.
Event B: Ticket picked is multiple of 5.

Now P(A) = {3,6,9,12,15,18} = 6/20.
And P(B) = {5,10,15,20} = 4/20.

Since in P(A) & P(B) we could see 15 to be common, we could conclude that the events are Mutually Exclusive..so for such Mutually Exclusive events the Addition Rule of Probability goes like this:

P(AUB) = P(A) + P(B) - P(A n B)

Where, P(A n B) always looks for what is common in two events, which is 15 in this case, so P(A n B) = 1/20.

Therefore, P(ticket picked is multiple of 3 or 5) = 6/20 + 4/20 - 1/20 = 9/20 is the answer.

Yes I too agree that 1/2 is the correct answer for this question.

(3, 6,9,12,15,18,5,10,15,20).
= 10/20,
= 1/2.

No. You are wrong Sundar.

Because, 15 has already consider once so there is no need to consider it again.

So the answer is 9/20.