Aptitude - Probability - Discussion
Discussion Forum : Probability - General Questions (Q.No. 5)
5.
Three unbiased coins are tossed. What is the probability of getting at most two heads?
Answer: Option
Explanation:
Here S = {TTT, TTH, THT, HTT, THH, HTH, HHT, HHH}
Let E = event of getting at most two heads.
Then E = {TTT, TTH, THT, HTT, THH, HTH, HHT}.
 P(E) = |
n(E) | = | 7 | . |
| n(S) | 8 |
Discussion:
121 comments Page 8 of 13.
Mohan said:
10 years ago
TTT there is no heads then why we consider that.
Sridevi said:
7 years ago
Why we have to take (TTT) ?
I can't understand.
I can't understand.
Sonali malviya said:
1 decade ago
Can anybody tell me why we have taken n(e) = 7?
Upendra said:
6 years ago
Could we use binomial probability distribution?
Venkat said:
1 decade ago
Answer is 3/8 i.e. (C).
H T H.
H H T.
T H H.
H T H.
H H T.
T H H.
Joel said:
1 decade ago
At most 2 heads, so how did you include HHH?
Praveen said:
9 years ago
Give the sample space of the given problem.
Trupti said:
9 years ago
Why zero will be accepted? Please tell me.
Taz said:
7 years ago
Very clear explanation. Thank you @Sundar.
Swetha said:
1 decade ago
Very clear explanation sundar..Thank you!
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