Aptitude - Probability - Discussion
Discussion Forum : Probability - General Questions (Q.No. 5)
5.
Three unbiased coins are tossed. What is the probability of getting at most two heads?
Answer: Option
Explanation:
Here S = {TTT, TTH, THT, HTT, THH, HTH, HHT, HHH}
Let E = event of getting at most two heads.
Then E = {TTT, TTH, THT, HTT, THH, HTH, HHT}.
 P(E) = |
n(E) | = | 7 | . |
| n(S) | 8 |
Discussion:
122 comments Page 8 of 13.
Venkatesh said:
1 decade ago
Why to consider the THT, TTH, HTT, TTT?
Namgay said:
1 decade ago
We know there are 8 combinations but What is the trick to get the combinations when we toss three coins like HHH TTH?
Yadlapalli sivateja said:
1 decade ago
To HHH condition:
H (1/2).
H (1/2)+3!/3! = 1/8.
H (1/2) answer = 1/8+3/8 = 1/2.
To TTH condition:
T(1/2).
T(1/2)+3!/2! = 3/8.
T (1/2).
H (1/2).
H (1/2)+3!/3! = 1/8.
H (1/2) answer = 1/8+3/8 = 1/2.
To TTH condition:
T(1/2).
T(1/2)+3!/2! = 3/8.
T (1/2).
Ankush said:
1 decade ago
Atleast two tails means?
Sarma said:
1 decade ago
3/4 is the answer.
Why are you considering TTT as a possible case?
Why are you considering TTT as a possible case?
Rushikesh said:
10 years ago
How should we accept as zero heads?
XYZ said:
10 years ago
Can anyone tell me the combination of three unbiased coins?
Jyotsna said:
10 years ago
Thank you @Sundar.
Your explanation is clear and simple.
Your explanation is clear and simple.
Chinenye said:
10 years ago
Why count 0, 0 means nothing?
Trupti said:
10 years ago
Why zero will be accepted? Please tell me.
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