Aptitude - Probability - Discussion

Discussion Forum : Probability - General Questions (Q.No. 5)
5.
Three unbiased coins are tossed. What is the probability of getting at most two heads?
3
4
1
4
3
8
7
8
Answer: Option
Explanation:

Here S = {TTT, TTH, THT, HTT, THH, HTH, HHT, HHH}

Let E = event of getting at most two heads.

Then E = {TTT, TTH, THT, HTT, THH, HTH, HHT}.

P(E) = n(E) = 7 .
n(S) 8

Discussion:
121 comments Page 5 of 13.

Riems said:   1 decade ago
Is there any direct method for calculating it? Because calculating n(e) may get confused in the exams time.

Manju said:   1 decade ago
How many times a man can tossing a coin so that the probability of atleast one head is more than 80%?

Sambit said:   9 years ago
But in explaining in the event there is TTT is included that is the wrong HHH is included is correct.

Afsha said:   7 years ago
At most means not more than;

Here, it's not more than 2. Thus, n(E) = 3.
Therefore, p(E) = 3/8.

Chelsia said:   2 years ago
We can get quickly the number of events like 2 to the Power of (number of coins).

I.e 2'3=> 8.
(7)

Abhijit said:   1 decade ago
Total no of probabilities= 2^3 =8
for 2/1/0 heads probability is =7(only 1 left HHH)

Trusha said:   10 years ago
Hi guys I'm totally confused about 'or' and 'and' concept can anyone help please?

Kishore said:   1 decade ago
If the meaning of unbiased coin is different coins then the answer is correct.

Asmi said:   2 years ago
At most means not more than 2 heads.

And at least means more than 2 heads.
(24)

Arnika said:   7 years ago
I can't understand this, please anyone help me to get the answer clearly.


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