Aptitude - Probability - Discussion
Discussion Forum : Probability - General Questions (Q.No. 5)
5.
Three unbiased coins are tossed. What is the probability of getting at most two heads?
Answer: Option
Explanation:
Here S = {TTT, TTH, THT, HTT, THH, HTH, HHT, HHH}
Let E = event of getting at most two heads.
Then E = {TTT, TTH, THT, HTT, THH, HTH, HHT}.
 P(E) = |
n(E) | = | 7 | . |
| n(S) | 8 |
Discussion:
122 comments Page 3 of 13.
Abdul Wahab said:
3 months ago
We can answer this question by using the Binomial Distribution.
3 x 1/4 x 1/2 = 3/8.
3 x 1/4 x 1/2 = 3/8.
(2)
Puttz said:
1 decade ago
Unbiased coins means a coin having head and tail whereas a biased coin means having two heads or two tails respectively.
(1)
Belle said:
9 years ago
Hi, can anyone solve this?
A couple has 3 children. Find each probability:
a. All boys.
b. All girls and boys.
c. Exactly 2 boys or 2 girls.
d. At least 1 child of each gender.
A couple has 3 children. Find each probability:
a. All boys.
b. All girls and boys.
c. Exactly 2 boys or 2 girls.
d. At least 1 child of each gender.
(1)
Lingesh kumar said:
6 years ago
What is unbaised coins?
(1)
Triveni said:
3 years ago
I can't Understand this. Anyone, please help me to get this.
(1)
Malarvizhi said:
2 decades ago
How did say n(s) is 8?
Sundar said:
2 decades ago
@Malarvizhi
Note: "At most two heads" --(means)--> Not more than two heads.
Here S = {TTT, TTH, THT, HTT, THH, HTH, HHT, HHH} <--- (8 combinations)
Therefore, n(S) = 8.
Note: "At most two heads" --(means)--> Not more than two heads.
Here S = {TTT, TTH, THT, HTT, THH, HTH, HHT, HHH} <--- (8 combinations)
Therefore, n(S) = 8.
Abhijit said:
2 decades ago
Total no of probabilities= 2^3 =8
for 2/1/0 heads probability is =7(only 1 left HHH)
for 2/1/0 heads probability is =7(only 1 left HHH)
Dharini said:
2 decades ago
I cant follow what abhijit said why it is 2 power 3?
Murugesh said:
2 decades ago
@dharini...
2---> H & T
3---> total no of coins.
so 2^3.
2---> H & T
3---> total no of coins.
so 2^3.
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