Aptitude - Probability - Discussion

Discussion Forum : Probability - General Questions (Q.No. 5)
5.
Three unbiased coins are tossed. What is the probability of getting at most two heads?
3
4
1
4
3
8
7
8
Answer: Option
Explanation:

Here S = {TTT, TTH, THT, HTT, THH, HTH, HHT, HHH}

Let E = event of getting at most two heads.

Then E = {TTT, TTH, THT, HTT, THH, HTH, HHT}.

P(E) = n(E) = 7 .
n(S) 8

Discussion:
121 comments Page 3 of 13.

Vivek Rai said:   5 years ago
But it says heads that mean only head should be counted not the tail side of the coin as we know a coin has 2 side head and tail and the question is asking about at most 2 heads so it should be = 3/8.

Anyone, please clarify my doubts.
(3)

Sriram said:   5 years ago
@sara.

We can get 2 heads any position out of 3 (- - -) each position has 1/2 probability. So, (1/2*1/2*1/2) + (1/2*1/2*1/2) + (1/2*1/2*1/2) =3/8.

Do the same way for 1 head (1 out of 3 positions) is (1/2*1/2*1/2) + (1/2*1/2*1/2) + (1/2*1/2*1/2) =3/8.

And last without a head is 1/8.

Add (atmost 2 to atlast 0) 1/8+3/8+3/8=7/8.

Upendra said:   5 years ago
Could we use binomial probability distribution?

Jaya said:   6 years ago
Thank you for your explanation @Sundhar.

Aman Gupta said:   6 years ago
At most two head means that 2 or more than 2 heads are accepted but no coins are not haed or one head are not accepted.

Lingesh kumar said:   6 years ago
What is unbaised coins?
(1)

Prashansa said:   6 years ago
I am not understanding this. Please, someone, help me.

Madhu said:   6 years ago
What is unbiased coins?

Can anyone please answer me.

Javeed said:   6 years ago
In coins, we have 2 sides so 2, and how many coins they gave in the question is 3 so 2^3 = 8.

And the number HH is 7 so 7/8 is answer.

Kharkhanhimel said:   6 years ago
Thanks all.


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