Aptitude - Probability - Discussion
Discussion Forum : Probability - General Questions (Q.No. 5)
5.
Three unbiased coins are tossed. What is the probability of getting at most two heads?
Answer: Option
Explanation:
Here S = {TTT, TTH, THT, HTT, THH, HTH, HHT, HHH}
Let E = event of getting at most two heads.
Then E = {TTT, TTH, THT, HTT, THH, HTH, HHT}.
 P(E) = |
n(E) | = | 7 | . |
| n(S) | 8 |
Discussion:
121 comments Page 11 of 13.
Jyoti said:
1 decade ago
Is there any short way to get (s) ?. This way takes much time.
Ravi said:
1 decade ago
You ask most two head but why you considered zero head?
Sujit said:
1 decade ago
SOURAV
If NOW will be together all the time all the time then take "NOW" as one letter. Lucknow will be considered as 5 letters. Then you can get the answer easily.
If NOW will be together all the time all the time then take "NOW" as one letter. Lucknow will be considered as 5 letters. Then you can get the answer easily.
Manju said:
1 decade ago
How many times a man can tossing a coin so that the probability of atleast one head is more than 80%?
Saurabh patel said:
1 decade ago
If the leatter of the word LUCKNOW are randomly arrenged, find the proabibility of always having the word NOW.
Arpan said:
1 decade ago
Abhijeet that's not the way to do this prob. You got it totally wrong. But your answer is matching. Have a look at Sundar's answer.
Uday said:
1 decade ago
How we can do with this ^ symbol ?
Swetha said:
1 decade ago
Very clear explanation sundar..Thank you!
Kruvy said:
1 decade ago
@Sundar , I like the way you explained. thanks mate.
Durgaprasad said:
1 decade ago
Thanks sundar. Superb explanation.
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