Aptitude - Pipes and Cistern - Discussion

Discussion Forum : Pipes and Cistern - General Questions (Q.No. 6)
6.
Two pipes can fill a tank in 20 and 24 minutes respectively and a waste pipe can empty 3 gallons per minute. All the three pipes working together can fill the tank in 15 minutes. The capacity of the tank is:
60 gallons
100 gallons
120 gallons
180 gallons
Answer: Option
Explanation:

Work done by the waste pipe in 1 minute = 1 - 1 + 1
15 20 24

    = 1 - 11
15 120

    = -  1 .    [-ve sign means emptying]
40

Volume of 1 part = 3 gallons.
40

Volume of whole = (3 x 40) gallons = 120 gallons.

Discussion:
48 comments Page 3 of 5.

Nitin said:   9 years ago
L.C.M of 20, 15, 24 = 120 unit total capacity.

120/3 = 40.
40 * 3 = 120.

Sindhu said:   9 years ago
Why making the values in the ratio one we get.

C = 1/15 - (1/20 + 1/24).

S.n.raju said:   9 years ago
Given,

First pipe takes 20h.
Second pipe take 24h.

ALL together take 15h.

Assuming that capacity of tank L. C. M [20, 24, 15] = 120.

First pipe can fill 6u/m.
Second pipe fill 5u/m.

All three fill 8u/m -------> 1.

First and second together fill in 11m/u----------> 2.

From 1 and 2 we get;

Third pipe fills the tank in 3u/m that is 120/3 = 40u of total fill.

But given 3 gallons are empty.

3 * 40 = 120gallons (capacity of tank).

ASHUTOSH SAHANI said:   9 years ago
120 gallon is waste water, which drains out from the tank in 15 min.

Nasir said:   9 years ago
Let, the capacity of the tank is x gallon.

3 pipes 1 min can fill up (1 / 20 +1 / 24 - 3),

So, 15 min can fill up, 15 (1 / 20 + 1 / 24 - 3),

We get 15 (1 / 20 + 1 / 24 - 3) equally to x.

We get the calculation of x is 120 gallons.
(1)

Aqueeb Khan said:   9 years ago
How can we solve this problem by the unitary method?

Md.gohor rizvi. said:   9 years ago
Let the capacity of the tank or pump X gallons.
The first pipe can fill the tank in 20 min.
The second pipe can fill the tank in 24 min.
1st pipe 20 min. fill X gallon. So, First pipe in one min can fill X/20 gallons.
So, the second pipe can fill in X/24 gallons.
And the third pipe flows out 3 gallons per minute.
So, X/20 + X/24 - 3 equal X/15 therefore X equal 120 gallons.

Siddhesh said:   8 years ago
The part of tank filled in 1 min by all pipes=(1/20)+(1/24)-(1/x).
= (44x-480)/480x.

The time required to fill 1 tank.
= 480x/(44x-480) minutes.

Where, x = time in minutes required to empty the tank by the waste pipe.
But all pipes fill the total tank in 15 minutes.

So, 15 = 480x/(44x-480).
x = 40 minutes.

The capacity of tank = discharge per minute * time.
= 3 * 40,
= 120 gallons.

Pritesh Bhawsar said:   8 years ago
I have the best solution here.
take LCM of 20,24 = 120

Pipe c can empty 3 gallon/minute.
120/3 = 40 minute.
-----------------------------|
minute | efficiency |
-------------|---------------|
a = 20 | 6 |
b = 24 | 5 |
c = 40 | 3 |
******************************
(a+b-c) --> 11-3 = (+8)

120/8 = 15 minute.

120-gallon tank will fill in 15 minutes,
A can fill in 24 minutes or 5 gallons/minute,
B can fill in 20 minutes or 6 gallons/minute.

C can empty in 40 minutes or 3 gallons/minute <---question says.
(1)

Tubai said:   8 years ago
Your logic is most acceptable or easy to me, Thanks @Rabi.


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