Aptitude - Pipes and Cistern - Discussion
Discussion Forum : Pipes and Cistern - General Questions (Q.No. 6)
6.
Two pipes can fill a tank in 20 and 24 minutes respectively and a waste pipe can empty 3 gallons per minute. All the three pipes working together can fill the tank in 15 minutes. The capacity of the tank is:
Answer: Option
Explanation:
Work done by the waste pipe in 1 minute = | 1 | - | ![]() |
1 | + | 1 | ![]() |
15 | 20 | 24 |
= | ![]() |
1 | - | 11 | ![]() |
15 | 120 |
= - | 1 | . [-ve sign means emptying] |
40 |
![]() |
1 | part = 3 gallons. |
40 |
Volume of whole = (3 x 40) gallons = 120 gallons.
Discussion:
48 comments Page 3 of 5.
Nitin said:
9 years ago
L.C.M of 20, 15, 24 = 120 unit total capacity.
120/3 = 40.
40 * 3 = 120.
120/3 = 40.
40 * 3 = 120.
Sindhu said:
9 years ago
Why making the values in the ratio one we get.
C = 1/15 - (1/20 + 1/24).
C = 1/15 - (1/20 + 1/24).
S.n.raju said:
9 years ago
Given,
First pipe takes 20h.
Second pipe take 24h.
ALL together take 15h.
Assuming that capacity of tank L. C. M [20, 24, 15] = 120.
First pipe can fill 6u/m.
Second pipe fill 5u/m.
All three fill 8u/m -------> 1.
First and second together fill in 11m/u----------> 2.
From 1 and 2 we get;
Third pipe fills the tank in 3u/m that is 120/3 = 40u of total fill.
But given 3 gallons are empty.
3 * 40 = 120gallons (capacity of tank).
First pipe takes 20h.
Second pipe take 24h.
ALL together take 15h.
Assuming that capacity of tank L. C. M [20, 24, 15] = 120.
First pipe can fill 6u/m.
Second pipe fill 5u/m.
All three fill 8u/m -------> 1.
First and second together fill in 11m/u----------> 2.
From 1 and 2 we get;
Third pipe fills the tank in 3u/m that is 120/3 = 40u of total fill.
But given 3 gallons are empty.
3 * 40 = 120gallons (capacity of tank).
ASHUTOSH SAHANI said:
9 years ago
120 gallon is waste water, which drains out from the tank in 15 min.
Nasir said:
9 years ago
Let, the capacity of the tank is x gallon.
3 pipes 1 min can fill up (1 / 20 +1 / 24 - 3),
So, 15 min can fill up, 15 (1 / 20 + 1 / 24 - 3),
We get 15 (1 / 20 + 1 / 24 - 3) equally to x.
We get the calculation of x is 120 gallons.
3 pipes 1 min can fill up (1 / 20 +1 / 24 - 3),
So, 15 min can fill up, 15 (1 / 20 + 1 / 24 - 3),
We get 15 (1 / 20 + 1 / 24 - 3) equally to x.
We get the calculation of x is 120 gallons.
(1)
Aqueeb Khan said:
9 years ago
How can we solve this problem by the unitary method?
Md.gohor rizvi. said:
9 years ago
Let the capacity of the tank or pump X gallons.
The first pipe can fill the tank in 20 min.
The second pipe can fill the tank in 24 min.
1st pipe 20 min. fill X gallon. So, First pipe in one min can fill X/20 gallons.
So, the second pipe can fill in X/24 gallons.
And the third pipe flows out 3 gallons per minute.
So, X/20 + X/24 - 3 equal X/15 therefore X equal 120 gallons.
The first pipe can fill the tank in 20 min.
The second pipe can fill the tank in 24 min.
1st pipe 20 min. fill X gallon. So, First pipe in one min can fill X/20 gallons.
So, the second pipe can fill in X/24 gallons.
And the third pipe flows out 3 gallons per minute.
So, X/20 + X/24 - 3 equal X/15 therefore X equal 120 gallons.
Siddhesh said:
8 years ago
The part of tank filled in 1 min by all pipes=(1/20)+(1/24)-(1/x).
= (44x-480)/480x.
The time required to fill 1 tank.
= 480x/(44x-480) minutes.
Where, x = time in minutes required to empty the tank by the waste pipe.
But all pipes fill the total tank in 15 minutes.
So, 15 = 480x/(44x-480).
x = 40 minutes.
The capacity of tank = discharge per minute * time.
= 3 * 40,
= 120 gallons.
= (44x-480)/480x.
The time required to fill 1 tank.
= 480x/(44x-480) minutes.
Where, x = time in minutes required to empty the tank by the waste pipe.
But all pipes fill the total tank in 15 minutes.
So, 15 = 480x/(44x-480).
x = 40 minutes.
The capacity of tank = discharge per minute * time.
= 3 * 40,
= 120 gallons.
Pritesh Bhawsar said:
8 years ago
I have the best solution here.
take LCM of 20,24 = 120
Pipe c can empty 3 gallon/minute.
120/3 = 40 minute.
-----------------------------|
minute | efficiency |
-------------|---------------|
a = 20 | 6 |
b = 24 | 5 |
c = 40 | 3 |
******************************
(a+b-c) --> 11-3 = (+8)
120/8 = 15 minute.
120-gallon tank will fill in 15 minutes,
A can fill in 24 minutes or 5 gallons/minute,
B can fill in 20 minutes or 6 gallons/minute.
C can empty in 40 minutes or 3 gallons/minute <---question says.
take LCM of 20,24 = 120
Pipe c can empty 3 gallon/minute.
120/3 = 40 minute.
-----------------------------|
minute | efficiency |
-------------|---------------|
a = 20 | 6 |
b = 24 | 5 |
c = 40 | 3 |
******************************
(a+b-c) --> 11-3 = (+8)
120/8 = 15 minute.
120-gallon tank will fill in 15 minutes,
A can fill in 24 minutes or 5 gallons/minute,
B can fill in 20 minutes or 6 gallons/minute.
C can empty in 40 minutes or 3 gallons/minute <---question says.
(1)
Tubai said:
8 years ago
Your logic is most acceptable or easy to me, Thanks @Rabi.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers