Aptitude - Pipes and Cistern - Discussion

Discussion Forum : Pipes and Cistern - General Questions (Q.No. 10)
10.
Two pipes A and B can fill a tank in 15 minutes and 20 minutes respectively. Both the pipes are opened together but after 4 minutes, pipe A is turned off. What is the total time required to fill the tank?
10 min. 20 sec.
11 min. 45 sec.
12 min. 30 sec.
14 min. 40 sec.
Answer: Option
Explanation:

Part filled in 4 minutes = 4 1 + 1 = 7 .
15 20 15

Remaining part = 1 - 7 = 8 .
15 15

Part filled by B in 1 minute = 1
20

1 : 8 :: 1 : x
20 15

x = 8 x 1 x 20 = 10 2 min = 10 min. 40 sec.
15 3

The tank will be full in (4 min. + 10 min. + 40 sec.) = 14 min. 40 sec.

Discussion:
37 comments Page 3 of 4.

Sriganesh. S said:   5 years ago
Can anyone explain, why they multiplying 1 in (8/15) * (1*20)?

Revant said:   5 years ago
@Preeti.

Very clear solution. Thanks for explaining.
(1)

Mahi said:   1 decade ago
Thanks kalapana your solution is time consuming.

Anjali said:   1 decade ago
Hi Kalpna,

How you write 44/3 = 14 min 40 sec ?

Priya P. said:   1 decade ago
@ kalpna.

Thanks. Really less time consuming.
(1)

Neha said:   9 years ago
How to change the fraction value into minutes?

Leela said:   8 years ago
Can anyone tell me why do we equate to one?

Venky said:   8 years ago
Can anyone explain it in easy method?

Teju said:   1 decade ago
Can anybody explain 1/20:8/15::1:x?

Manisha said:   8 years ago
It is clear now Thank you, @Ashim.


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