Aptitude - Permutation and Combination - Discussion
Discussion Forum : Permutation and Combination - General Questions (Q.No. 4)
4.
Out of 7 consonants and 4 vowels, how many words of 3 consonants and 2 vowels can be formed?
Answer: Option
Explanation:
Number of ways of selecting (3 consonants out of 7) and (2 vowels out of 4)
| = (7C3 x 4C2) | |||||||||
|
|||||||||
| = 210. |
Number of groups, each having 3 consonants and 2 vowels = 210.
Each group contains 5 letters.
| Number of ways of arranging 5 letters among themselves |
= 5! |
| = 5 x 4 x 3 x 2 x 1 | |
| = 120. |
Required number of ways = (210 x 120) = 25200.
Video Explanation: https://youtu.be/dm-8T8Si5lg
Discussion:
65 comments Page 6 of 7.
Mansi said:
1 decade ago
What is the difference between permutation and combination? I always get confused.
Akhila said:
1 decade ago
How can we find the given problem is from permutation or combination?
Sagar said:
1 decade ago
If it was mentioned distinct in the question can we use 7p3*4p2.
Mohan said:
9 years ago
It's.
VCVCC
VCVCV
VCCVC
VCCCV
CVVCC
CCVVC
CCVVC
CCVCV
CCcvv
VCVCC
VCVCV
VCCVC
VCCCV
CVVCC
CCVVC
CCVVC
CCVCV
CCcvv
Jyoti bala said:
1 decade ago
When we apply permutation and combination? please tell me one.
Himatheja said:
8 years ago
4C2 = (3*4)/(2! * 2!).
2 VOWELS OUT OF 4.
then, why 210?
2 VOWELS OUT OF 4.
then, why 210?
(1)
Mihul said:
7 years ago
Why at 7p3 4 is excluded can anyone help me with this?
(3)
Benni said:
1 decade ago
How can we find permutation and combination problem ?
Spurthy said:
1 decade ago
I cannot get you, after what you said after 120 ways?
Student said:
1 decade ago
Why we need multiply 120 with 210 is it necessary?
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