Aptitude - Permutation and Combination - Discussion

Discussion Forum : Permutation and Combination - General Questions (Q.No. 7)
7.
How many 3-digit numbers can be formed from the digits 2, 3, 5, 6, 7 and 9, which are divisible by 5 and none of the digits is repeated?
5
10
15
20
Answer: Option
Explanation:

Since each desired number is divisible by 5, so we must have 5 at the unit place. So, there is 1 way of doing it.

The tens place can now be filled by any of the remaining 5 digits (2, 3, 6, 7, 9). So, there are 5 ways of filling the tens place.

The hundreds place can now be filled by any of the remaining 4 digits. So, there are 4 ways of filling it.

Required number of numbers = (1 x 5 x 4) = 20.

Discussion:
88 comments Page 7 of 9.

Karthick said:   9 years ago
How many 4 digit no can be formed with digits 1, 2, 3,4,5 which are divisible by 4 and digits not repeated?

a)144 b) 168 c) 182 d) none

Please tell me the correct answer.

Manisha said:   9 years ago
Nice answer@Justin.

Monisha said:   9 years ago
@Karthick.

Since last two digits must be 12 or 24 or 32 or 52,

The other two digits must be filled with either of the 3 numbers,

Thus,
(3*2)+(3*2)+(3*2)+(3*2) = 24 ways.

And hence the answer is none.

Joe said:   9 years ago
Why isn't it just 5C2, from the 5 numbers that arent 5 to go in tens and hundreds, and picking two?

Vignesh said:   8 years ago
Please explain me, what would happen if another digit (0) is added to the series, i.e., 2,3,6,7,9,5 and 0 and the digits are to arranged without repetition such that the 3 digit number is divisible by 5?

Ambika said:   8 years ago
Write all the possible number using the digit 7, 0, 6 repetition of digits is not allowed.

Xiya said:   8 years ago
Can anyone say is 20 the right answer?

Because the question asked is number divisible by 5 and also not repeated?
(1)

Dema said:   8 years ago
How 5p2? Please explain.

Pranav Khurud said:   8 years ago
If question is like, How many 3-digit numbers can be formed from the digits 2, 3, 5, 6, 7, 0, and 9, which are divisible by 5 and none of the digits is repeated?, In this situation unit place may be 0 or 5.

Shantanu said:   8 years ago
How many five digit numbers can be formed by using digits 0, 1, 2, 3, 4 and 5 without repetition. And number should be divisible by 6.

Can anyone solve this?


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