Aptitude - Permutation and Combination - Discussion
Discussion Forum : Permutation and Combination - General Questions (Q.No. 1)
1.
From a group of 7 men and 6 women, five persons are to be selected to form a committee so that at least 3 men are there on the committee. In how many ways can it be done?
Answer: Option
Explanation:
We may have (3 men and 2 women) or (4 men and 1 woman) or (5 men only).
 Required number of ways |
= (7C3 x 6C2) + (7C4 x 6C1) + (7C5) | |||||||||||
|
||||||||||||
|
||||||||||||
| = (525 + 210 + 21) | ||||||||||||
| = 756. |
Discussion:
137 comments Page 5 of 14.
Ali said:
8 years ago
@Harsh.
I think we need to multiply so that we get the total number of ways we can choose 3 men from a total of 13 men and women.
I think we need to multiply so that we get the total number of ways we can choose 3 men from a total of 13 men and women.
Shoeib said:
8 years ago
Yeah, I too agree @Harsh.
Harsh said:
8 years ago
It's correct that we select 3 men from 7 and 2 women from 6. But why do we need to multiply it to get total no of ways?
Rutuja said:
9 years ago
Someone, please give the solution.
In a group of 6 people, there are 3 Indians and 3 Chinese. How many subsets can be created such that there are at least 1 Indian in each subset?
In a group of 6 people, there are 3 Indians and 3 Chinese. How many subsets can be created such that there are at least 1 Indian in each subset?
Abhimanyu said:
9 years ago
756 WILL BE CORRECT.
35 * 15 + 35 * 6 + 21= 756.
35 * 15 + 35 * 6 + 21= 756.
Ishak said:
9 years ago
Remarked first line 7c5 second line 7c2. How?
Siva kumar said:
9 years ago
Nice solution @Nagu.
Kiprono Langat Esau said:
9 years ago
Kindly, solve this.
The committee of six is to be formed from a group of seven engineers and four mathematicians, how many different committees can be formed if at least two mathematicians are always to be included?
The committee of six is to be formed from a group of seven engineers and four mathematicians, how many different committees can be formed if at least two mathematicians are always to be included?
Fatmata sorie said:
9 years ago
Where do you get from 35?
Anil said:
9 years ago
@Malu.
The problem says at least 3 men so if you select 5 women it would contradiction to the problem.
The problem says at least 3 men so if you select 5 women it would contradiction to the problem.
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