Aptitude - Permutation and Combination - Discussion
Discussion Forum : Permutation and Combination - General Questions (Q.No. 10)
10.
In how many different ways can the letters of the word 'DETAIL' be arranged in such a way that the vowels occupy only the odd positions?
Answer: Option
Explanation:
There are 6 letters in the given word, out of which there are 3 vowels and 3 consonants.
Let us mark these positions as under:
(1) (2) (3) (4) (5) (6)
Now, 3 vowels can be placed at any of the three places, marked 1, 3, 5.
Number of ways of arranging the vowels = 3P3 = 3! = 6.
Also, the 3 consonants can be arranged at the remaining 3 positions.
Number of ways of these arrangements = 3P3 = 3! = 6.
Total number of ways = (6 x 6) = 36.
Discussion:
59 comments Page 5 of 6.
Jilsa said:
8 years ago
What if we want to arrange letters of *Machine* such that vowels occupy odd places?
Usha said:
7 years ago
Then what is the use of vowels arranged in odd position?
I think it's wrong.
I think it's wrong.
PRAKASH S said:
1 decade ago
I really don't understand why we are doing that.
How we are taken 3p3 = 6?
How we are taken 3p3 = 6?
Subhadeep said:
1 decade ago
We can consider the seventh position also. So I feel the answer is wrong.
Aditya said:
9 years ago
How can we solve the same question taking 'FATHER' as the given word?
Dev said:
10 years ago
It can be done by 6x5x4x3x2 divide by 2 and again divide by 10 = 36.
Omshiva said:
6 years ago
@Keshav.
By Using the Gauss method. The correct answer is A.
By Using the Gauss method. The correct answer is A.
(6)
Navi said:
7 years ago
Simple:
(DTL) * (EAI).
(3*2*1) * (3*2*1).
(6)*(6) = 36.
(DTL) * (EAI).
(3*2*1) * (3*2*1).
(6)*(6) = 36.
(2)
Bonface said:
9 years ago
Why we also considering the positions of the consonants?
Gayathri said:
1 decade ago
Why we use permutation concept instead of combination.
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