Aptitude - Permutation and Combination - Discussion
Discussion Forum : Permutation and Combination - General Questions (Q.No. 5)
5.
In how many ways can the letters of the word 'LEADER' be arranged?
Answer: Option
Explanation:
The word 'LEADER' contains 6 letters, namely 1L, 2E, 1A, 1D and 1R.
 Required number of ways = |
6! | = 360. |
| (1!)(2!)(1!)(1!)(1!) |
Video Explanation: https://youtu.be/2_2QukHfkYA
Discussion:
84 comments Page 8 of 9.
Manish said:
8 years ago
7 letters out of which 2 letters are repeated.
Therefore 7!/2!
Therefore 7!/2!
Manish said:
8 years ago
If vowels point is given then vowel to be treated as one-word & if that one word contains repeat letters they must be divided.
For eg- eeo.
3!/2!.
For eg- eeo.
3!/2!.
Asam said:
7 years ago
Please explain this.
Dadasaheb Maske said:
7 years ago
Explain
(1)
Anandavalli said:
7 years ago
But E and A are vowels so we have to take it as 1, right?
(1)
Aswathy said:
7 years ago
Hi, I am not getting this, Please explain this answer clearly.
(1)
Yuvraj k said:
7 years ago
I think the Answer is 720.
Raj Kumar said:
6 years ago
The answer is 360 because here in question 'e' is coming twice.
(3)
Julius said:
6 years ago
In how many ways can the word obasanjo be arranged so that the vowels will never come together.
(4)
Yaswanth said:
6 years ago
LEADER consist of 6 words,
In that 2E's so,
6!/2! = 720/2 = 360.
In that 2E's so,
6!/2! = 720/2 = 360.
(1)
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