Aptitude - Permutation and Combination - Discussion
Discussion Forum : Permutation and Combination - General Questions (Q.No. 5)
5.
In how many ways can the letters of the word 'LEADER' be arranged?
Answer: Option
Explanation:
The word 'LEADER' contains 6 letters, namely 1L, 2E, 1A, 1D and 1R.
 Required number of ways = |
6! | = 360. |
| (1!)(2!)(1!)(1!)(1!) |
Video Explanation: https://youtu.be/2_2QukHfkYA
Discussion:
84 comments Page 8 of 9.
Achutharaj said:
1 decade ago
Hi poornima,
E is repeated in two times so we divided
leader -l,e,a,d,r ( e is repeted 2 times so considered single time)
6!=6x5x4x3x2x1/2x1=360
E is repeated in two times so we divided
leader -l,e,a,d,r ( e is repeted 2 times so considered single time)
6!=6x5x4x3x2x1/2x1=360
Poornima.R said:
1 decade ago
Why we want to divide this 720 by 2?
Vinny said:
1 decade ago
LEADER contains 6 letters.
So 2 are similar letters.
Therefore 6!/2!=360.
So 2 are similar letters.
Therefore 6!/2!=360.
Sonu said:
1 decade ago
Ritu explain it in a very gooo way thanks a lot ritu.
Praveen said:
1 decade ago
We can't divide by 2 may be what not 5!?
Umakant said:
1 decade ago
In this Method
6*5*4*3*2*1=720
720/2=360
Why divide by 2
Please explain it
6*5*4*3*2*1=720
720/2=360
Why divide by 2
Please explain it
Umakant said:
1 decade ago
Why is wrong 5x4x3x2x1?
Ritu said:
1 decade ago
6*5*4*3*2*1=720
720/2=360
720/2=360
Sam said:
1 decade ago
Leader has 6 letters so it can be arranged in 6! ways but letter e is repeated twice so ans is 6!/2!=360.
Sunil said:
1 decade ago
Explain Please
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