Aptitude - Permutation and Combination - Discussion
Discussion Forum : Permutation and Combination - General Questions (Q.No. 5)
5.
In how many ways can the letters of the word 'LEADER' be arranged?
Answer: Option
Explanation:
The word 'LEADER' contains 6 letters, namely 1L, 2E, 1A, 1D and 1R.
 Required number of ways = |
6! | = 360. |
| (1!)(2!)(1!)(1!)(1!) |
Video Explanation: https://youtu.be/2_2QukHfkYA
Discussion:
84 comments Page 5 of 9.
Mukund said:
1 decade ago
Whether we need to divide by 2 or 2!. As in this, it doesn't matter but if "e" was repeated thrice, then do we need to divide numerator by 3 or 3!
Kelvin esekon said:
10 years ago
The word as 6 letters, the letter e is repeated twice, so:
npr = 6!/2! = 360.
npr = 6!/2! = 360.
Paulvannan said:
9 years ago
Hi factorial value is 1*2*36*4*5*6* = 720.
So 720/2 = 360.
So 720/2 = 360.
JONSE said:
9 years ago
6!/2! = 6*5*4*3*2*1/2.
= 720/2.
= 360.
= 720/2.
= 360.
Savitri said:
9 years ago
@Sundar, Can you please explain this, how it is 72?
= 5! - 4! x 2!.
= 72.
= 5! - 4! x 2!.
= 72.
Savitri said:
9 years ago
(1!)(2!)(1!)(1!)(1!)
How it is? Explain me.
How it is? Explain me.
Divya said:
9 years ago
@Savitri.
It is;
L = 1.
E = 2.
A = 1.
D = 1.
R = 1.
It is;
L = 1.
E = 2.
A = 1.
D = 1.
R = 1.
Dipankar Rabha said:
9 years ago
How did 360 come?
What is (1!)? What is the meant of this symbol? And can anyone provide the easy method for this type of problem?
What is (1!)? What is the meant of this symbol? And can anyone provide the easy method for this type of problem?
Sandeep said:
9 years ago
I have a query.
LEADER= (LADR) +) (EE) = 4 + 1 = 5! = 120, and divided it by 2C2!, why can't be the answer 120.
The same way for CORPORATION problem is solved. All vowels are a set & consonants are of another set and as the vowels are scrambled it was divided by vowels combinations.
LEADER= (LADR) +) (EE) = 4 + 1 = 5! = 120, and divided it by 2C2!, why can't be the answer 120.
The same way for CORPORATION problem is solved. All vowels are a set & consonants are of another set and as the vowels are scrambled it was divided by vowels combinations.
Manoj D Desai said:
9 years ago
Please See the question once carefully, it's just asked for number of ways so word repetition is not considered so the correct answer is 720 (6!) ,
If the question is asked like " How many DIFFERENT ways word Leader can be arranged" then it would have been 6!/2 for E-letter repeating 2 times.
If the question is asked like " How many DIFFERENT ways word Leader can be arranged" then it would have been 6!/2 for E-letter repeating 2 times.
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