Aptitude - Permutation and Combination - Discussion

Discussion Forum : Permutation and Combination - General Questions (Q.No. 5)
5.
In how many ways can the letters of the word 'LEADER' be arranged?
72
144
360
720
None of these
Answer: Option
Explanation:

The word 'LEADER' contains 6 letters, namely 1L, 2E, 1A, 1D and 1R.

Required number of ways = 6! = 360.
(1!)(2!)(1!)(1!)(1!)

Video Explanation: https://youtu.be/2_2QukHfkYA

Discussion:
84 comments Page 2 of 9.

Dadasaheb Maske said:   7 years ago
Explain
(1)

Parthiban said:   8 years ago
LEADER : totally 6 words so= 6!.
L1, E2, A1, D1, R1 so= 1!*2!*1!*1!*1!.
6!=6*5*4*3*2*1=720.
1!*2!*1!*1!*1!= (1*1) (2*1) (1*1) (1*1) (1*1)=2.
Total words=720/2=360.
(1)

Shivaraj kavalaga said:   9 years ago
@Savitri and @Divya.

Don't go that method because you'll get big confusion in solving big problems.

Vinny said:   1 decade ago
LEADER contains 6 letters.

So 2 are similar letters.

Therefore 6!/2!=360.

Vamshi said:   8 years ago
They didn't ask without repetition? Then why you divided by 2?

Ezaz Ahmed said:   8 years ago
Thanks for giving the explanation of the answer.

Shekhar said:   8 years ago
In how many ways can the letters of the word 'DIRECTOR', be arranged so that the vowels are never together? Please solve this.

Gowtham said:   8 years ago
@Khan.

The word SAMPLE has 6 letters so we apply the formula in 6!= 720 ways can we arranged.

Am I Right?

Prakash said:   9 years ago
Why we use permutation formula in this example?

Is there any way to solve this?

Khan said:   9 years ago
In how many ways the letter of the word SAMPLE be arranged if all the latter are taken?

Please slove with formula.


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