Aptitude - Permutation and Combination - Discussion

Discussion Forum : Permutation and Combination - General Questions (Q.No. 5)
5.
In how many ways can the letters of the word 'LEADER' be arranged?
72
144
360
720
None of these
Answer: Option
Explanation:

The word 'LEADER' contains 6 letters, namely 1L, 2E, 1A, 1D and 1R.

Required number of ways = 6! = 360.
(1!)(2!)(1!)(1!)(1!)

Video Explanation: https://youtu.be/2_2QukHfkYA

Discussion:
84 comments Page 2 of 9.

Sonu said:   1 decade ago
Ritu explain it in a very gooo way thanks a lot ritu.

Vinny said:   1 decade ago
LEADER contains 6 letters.

So 2 are similar letters.

Therefore 6!/2!=360.

Poornima.R said:   1 decade ago
Why we want to divide this 720 by 2?

Achutharaj said:   1 decade ago
Hi poornima,

E is repeated in two times so we divided
leader -l,e,a,d,r ( e is repeted 2 times so considered single time)
6!=6x5x4x3x2x1/2x1=360

Tezan said:   1 decade ago
Why we take 6!/2! Whay we have not take vowel 3 and consonent 3. like (3+1)4
4!= 4*3*2*1= 24
3!/2!=3
24*3= 72

Lalit said:   1 decade ago
Helo frndz in this word LEADER thre r 6 leters in which 2 leters are repeted thats why we divide it by 2! and the ans is 6!/2!

Tanaya said:   1 decade ago
I have query that all these problems belong to combination and not permutation section?

Abhishek said:   1 decade ago
Why not 5! * 2!? because E is repeated so now consider 5 letters so 5! and E is repeated twice so 2! ??

Sujit said:   1 decade ago
@Tanaya: both permutation and combination are used in this section.

In some problems we arrange the letters means they are of type permutation..and in some cases like selection group we used combination :-).

@Abhishek: let me explain you with the example

Suppose your name is : AAB which contain A 2 times (in above question E repeate 2 times so i consider name with one character repeat twice)

AAB can be arranged in

AAB ( 1)
ABA (2)
BAA (3)

Means 3 ways..

This ans can be calculate directly using formula

Formula:


(number of characters)!
------------------------
(number of repeat characters) !


In AAB there are 3 characters and one character repeat twice

So above formula become

3! 3*2*1
-- = ------ = 3 which we got above by doing manually
2! 2*1

similarly in above question

LEADER contains 6 character and E repeat twice so using formula

6!
--- = 360.
2!

Hope you got this :-).

Jonathan said:   1 decade ago
LEADER

One way of arranging this is
"EADERL" (The first 'E' and the second 'E')
If I want to put the second 'E' in place of the first 'E' to make another arrangement, I would get
"EADERL" which is the same as the previous one.

POINT: we have shown that eventhough I interchange the first 'E' and the second 'E', we came up with the same arrangement.
MEANING... if there are TWO same letters, there will be DUPLICATION...
That is the reason why we DIVIDE by TWO!

It's not 5! because still, there are six letters we are arranging!

Hope this insight can help you!:)


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