Aptitude - Percentage - Discussion
Discussion Forum : Percentage - General Questions (Q.No. 1)
1.
A batsman scored 110 runs which included 3 boundaries and 8 sixes. What percent of his total score did he make by running between the wickets?
Answer: Option
Explanation:
Number of runs made by running = 110 - (3 x 4 + 8 x 6)
= 110 - (60)
= 50.
 Required percentage = |
 |
50 | x 100 |  % = 45 |
5 | % |
| 110 | 11 |
Video Explanation: https://youtu.be/X2zTnABqEHU
Discussion:
151 comments Page 8 of 16.
Vikrant raushan said:
1 decade ago
@Jay. Answer to wheat problem.
Let x kg of 4.5 and y kg of 5.25 Rs variety.
So,
4.5x+5.25y = 5(x+y).
on solving we get,
0.25y = 0.5x.
(x/y) = 25/50.
x:y = 1:2.
Let x kg of 4.5 and y kg of 5.25 Rs variety.
So,
4.5x+5.25y = 5(x+y).
on solving we get,
0.25y = 0.5x.
(x/y) = 25/50.
x:y = 1:2.
Tejesh said:
1 decade ago
Total runs = 110.
Covered by = 60.
110-60 = 50.
So 50/1100*100.
45*5/11.
Covered by = 60.
110-60 = 50.
So 50/1100*100.
45*5/11.
Ash said:
1 decade ago
500/11
Hence we can write 500/11 = 45*5/11.
45
-----
11 ! 500
! 44
!----
60
55
-----
5
Hence we can write 500/11 = 45*5/11.
Rahul said:
1 decade ago
Any one explain how 45 is came?
Arulsevi said:
1 decade ago
Total runs = 110.
Runs got by boundary & sixes = 60//[4x3 + 8x6].
Runs got by wickets = 110-60 = 50.
They are asking what percentage 60 is what % of 110.
So, x% of 110 = 60.
x*110/100 = 60.
x = option B.
Runs got by boundary & sixes = 60//[4x3 + 8x6].
Runs got by wickets = 110-60 = 50.
They are asking what percentage 60 is what % of 110.
So, x% of 110 = 60.
x*110/100 = 60.
x = option B.
Chandu said:
1 decade ago
800 is how much % of 7200?
800*%/100 = 7200.
By solving we get 800%.
And by using above method.
800/7200*100=11.11111111.
Which will be the correct method and what is the answer.
800*%/100 = 7200.
By solving we get 800%.
And by using above method.
800/7200*100=11.11111111.
Which will be the correct method and what is the answer.
Harish said:
1 decade ago
3 boundaries means 3*4 = 12 runs.
8 sixes means 8*6 = 48 runs.
Totally we have 60 runs only with boundaries and sixes.
Now given runs are 110.
Hence total score did he make by running between the wickets is,
110-60 = 50 runs.
So the percentage is (50/110)*100= 45.454545....%.
We will write this like 45(5/11)%.
8 sixes means 8*6 = 48 runs.
Totally we have 60 runs only with boundaries and sixes.
Now given runs are 110.
Hence total score did he make by running between the wickets is,
110-60 = 50 runs.
So the percentage is (50/110)*100= 45.454545....%.
We will write this like 45(5/11)%.
Dheepthi said:
1 decade ago
Here the required percentage is 50/100*100 then how 45 will came?
Supriya said:
1 decade ago
How come 110?
Suseela said:
1 decade ago
110 is the total score made by batsman. Which included 3*4 boundaries = 12, 8*6 boundaries = 48.
In question, they have asked the running score percentage of the batsman between wickets. Hence we need only running score, we have to subtract those boundary values from total running score.
So, 110-3*4+8*6 = 50.
Now, 50 is running score out of total running score by the batsman so, 50/110. The and should be in percentage.
So 50/110*100 = 45%.
In question, they have asked the running score percentage of the batsman between wickets. Hence we need only running score, we have to subtract those boundary values from total running score.
So, 110-3*4+8*6 = 50.
Now, 50 is running score out of total running score by the batsman so, 50/110. The and should be in percentage.
So 50/110*100 = 45%.
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