Aptitude - Percentage - Discussion

Discussion Forum : Percentage - General Questions (Q.No. 1)
1.
A batsman scored 110 runs which included 3 boundaries and 8 sixes. What percent of his total score did he make by running between the wickets?
45%
45 5 %
11
54 6 %
11
55%
Answer: Option
Explanation:

Number of runs made by running = 110 - (3 x 4 + 8 x 6)

= 110 - (60)

= 50.

Required percentage = 50 x 100 % = 45 5 %
110 11

Video Explanation: https://youtu.be/X2zTnABqEHU

Discussion:
144 comments Page 7 of 15.

Sharath said:   9 years ago
@Harish.

Really fantastic and simple explanation.

Ramesh said:   9 years ago
@Jay

1 : 2 is answer.
(1)

Afrin said:   9 years ago
Why should we write 50/110 * 100?

As my knowledge to get a percentage of 50 in 110 we have to calculate as 50/100 * 110.

Rahul said:   9 years ago
45 * (5/11)% = 45.45% then why option B and why not option A?

Uday said:   9 years ago
Total score 110.

3 boundaries = (3 * 4) =12.
8 sixes = 8 * 6 = 48.
12 + 48 = 60.

Remaining runs (110 - 60) scored by running.

So % is 50/110 * 100 = 500/11 = option b.

Rajasekhar said:   9 years ago
Thank you @Aparna.

Mustapha dukuly said:   9 years ago
How do we know about 4, when it is not in the problem?

Eunice said:   9 years ago
Please, how did you get the 6 since it was not in the problem?

Esther said:   9 years ago
How do we know about 4, when it is not in the problem?

Surya tez said:   9 years ago
Let me explain.

Total runs made by him = 110 in which he made 3 boundaries and 8 sixes
So basically a boundary means 4, therefore 3 boundaries means 3 X 4 = 12.
And 8 sixes equals to 8 X 6 = 48.

Now adding boundary and sixes made by him,
Therefore 12 + 48 = 60.

So the score 60 was not made by runs.

So let us subtract the score 60 from the total score 110.
So that 110 - 60 = 50
50 is the score which is made by running between the wickets.

The solution is not yet completed, it's about to finish

We need to get a percentage of that runs made by him.

50/110 * 100 = 45 * 5/11 will be the answer.

Hope you understand.
(1)


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