Aptitude - Percentage - Discussion
Discussion Forum : Percentage - General Questions (Q.No. 1)
1.
A batsman scored 110 runs which included 3 boundaries and 8 sixes. What percent of his total score did he make by running between the wickets?
Answer: Option
Explanation:
Number of runs made by running = 110 - (3 x 4 + 8 x 6)
= 110 - (60)
= 50.
Required percentage = |
![]() |
50 | x 100 | % = 45 |
5 | % |
| 110 | 11 |
Video Explanation: https://youtu.be/X2zTnABqEHU
Discussion:
156 comments Page 14 of 16.
Arun said:
1 decade ago
Can any one explain me that how to convert decimal to fraction.
Sarah said:
1 decade ago
Is it just me or is this question impossible for those who have no knowledge on cricket terminology? i.e., 1 boundary means a score of 4?
Nikhila said:
1 decade ago
Hey the correct answer is option d.55%
explaination:x%of a number is given as :(x*number)/100 and not (x*100)/number..
for eg 10%of 20 is 2...therefore according to my formula its (10*20)/100=2 but according to the way the sum has been solved here its (10*100)/20=50...which is wrong how can 50 be 10%of 20????
therefore here its (50*110)/100=55%
explaination:x%of a number is given as :(x*number)/100 and not (x*100)/number..
for eg 10%of 20 is 2...therefore according to my formula its (10*20)/100=2 but according to the way the sum has been solved here its (10*100)/20=50...which is wrong how can 50 be 10%of 20????
therefore here its (50*110)/100=55%
(1)
Nagajyothi said:
1 decade ago
Thanks aprana your answer is very clear.
Nagabhushana said:
1 decade ago
Let given that 110
4*3=12
6*8=48
12+48=60
110-60=50
(50/110)*100%
=45*5/11%
4*3=12
6*8=48
12+48=60
110-60=50
(50/110)*100%
=45*5/11%
Raj said:
1 decade ago
Total scored = 110
runs made by boundary and six = 3*4+8*6
=60
then run scored by running b\w the wicket =110-60
=50
.)lets take an eg. to convert any integral or fractional value into percentage
as we know 1/100 = %
so
x/100 = x%
eg. 1/2 = {(1/2)*100}/100 = 50%
similarly 1/3=33.33%
.)5/6 = 1/2+1/3 = 50%+33.33% = 83.33%
.)3/8 = 12.5*3 = 37.5% (1/8=12.5%)
now carefully read the last line of Que. What percent of his total score did he make by running between the wickets?
so % required = {(50/110)*100}/100 = 45.45%
runs made by boundary and six = 3*4+8*6
=60
then run scored by running b\w the wicket =110-60
=50
.)lets take an eg. to convert any integral or fractional value into percentage
as we know 1/100 = %
so
x/100 = x%
eg. 1/2 = {(1/2)*100}/100 = 50%
similarly 1/3=33.33%
.)5/6 = 1/2+1/3 = 50%+33.33% = 83.33%
.)3/8 = 12.5*3 = 37.5% (1/8=12.5%)
now carefully read the last line of Que. What percent of his total score did he make by running between the wickets?
so % required = {(50/110)*100}/100 = 45.45%
Sundar said:
1 decade ago
An important interview question:
Question: 75% of a number when added to 75 becomes the number itself. The number is ?
Solution:
Let the required number be x.
x = 75% of x + 75
x = 75/100x + 75
1x = 0.75x + 75
1x - 0.75x = 75
0.25x = 75
x = 75/0.25
x = 7500/25
x = 300.
Verification:
75% of 300 = 275
Now 755 + 75 = 300
Hence 300 is the required answer.
Question: 75% of a number when added to 75 becomes the number itself. The number is ?
Solution:
Let the required number be x.
x = 75% of x + 75
x = 75/100x + 75
1x = 0.75x + 75
1x - 0.75x = 75
0.25x = 75
x = 75/0.25
x = 7500/25
x = 300.
Verification:
75% of 300 = 275
Now 755 + 75 = 300
Hence 300 is the required answer.
(1)
Rajeev said:
1 decade ago
3*4+8*6=60.
So answer will be (C).
So answer will be (C).
Jay said:
1 decade ago
In what ratio should wheat at Rs. 4.5 per kg be mixed with another variety at Rs. 5.25 per kg so that the mixture be worth of Rs. 5 per kg?
a. 1:2
b. 2:1
c. 1:3
d. 3:1.
Please anybody tel the answer with explanation.
a. 1:2
b. 2:1
c. 1:3
d. 3:1.
Please anybody tel the answer with explanation.
Rita shukla said:
1 decade ago
3*4=12,
8*6= 48
48+12=60
Total run b/w the wickets 110 - 60=50
Therefore %= 50/110* 100 = 45.454545
8*6= 48
48+12=60
Total run b/w the wickets 110 - 60=50
Therefore %= 50/110* 100 = 45.454545
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Required percentage =
% = 45