Aptitude - Percentage - Discussion

Discussion Forum : Percentage - General Questions (Q.No. 1)
1.
A batsman scored 110 runs which included 3 boundaries and 8 sixes. What percent of his total score did he make by running between the wickets?
45%
45 5 %
11
54 6 %
11
55%
Answer: Option
Explanation:

Number of runs made by running = 110 - (3 x 4 + 8 x 6)

= 110 - (60)

= 50.

Required percentage = 50 x 100 % = 45 5 %
110 11

Video Explanation: https://youtu.be/X2zTnABqEHU

Discussion:
144 comments Page 11 of 15.

Supriya said:   1 decade ago
How come 110?

Dheepthi said:   1 decade ago
Here the required percentage is 50/100*100 then how 45 will came?

Harish said:   1 decade ago
3 boundaries means 3*4 = 12 runs.
8 sixes means 8*6 = 48 runs.

Totally we have 60 runs only with boundaries and sixes.

Now given runs are 110.
Hence total score did he make by running between the wickets is,

110-60 = 50 runs.
So the percentage is (50/110)*100= 45.454545....%.

We will write this like 45(5/11)%.

Chandu said:   1 decade ago
800 is how much % of 7200?
800*%/100 = 7200.

By solving we get 800%.
And by using above method.

800/7200*100=11.11111111.
Which will be the correct method and what is the answer.

Arulsevi said:   1 decade ago
Total runs = 110.

Runs got by boundary & sixes = 60//[4x3 + 8x6].
Runs got by wickets = 110-60 = 50.

They are asking what percentage 60 is what % of 110.

So, x% of 110 = 60.
x*110/100 = 60.

x = option B.

Rahul said:   1 decade ago
Any one explain how 45 is came?

Ash said:   1 decade ago
500/11
    45
-----
11 ! 500
! 44
!----
60
55
-----
5

Hence we can write 500/11 = 45*5/11.

Tejesh said:   1 decade ago
Total runs = 110.
Covered by = 60.

110-60 = 50.
So 50/1100*100.

45*5/11.

Vikrant raushan said:   1 decade ago
@Jay. Answer to wheat problem.

Let x kg of 4.5 and y kg of 5.25 Rs variety.

So,

4.5x+5.25y = 5(x+y).

on solving we get,

0.25y = 0.5x.

(x/y) = 25/50.

x:y = 1:2.

Naveen said:   1 decade ago
11)500(45
495
___
5

Quotient*(remainder/division) = 45*5/11.


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