Aptitude - Percentage - Discussion

Discussion Forum : Percentage - General Questions (Q.No. 13)
13.
Gauri went to the stationers and bought things worth Rs. 25, out of which 30 paise went on sales tax on taxable purchases. If the tax rate was 6%, then what was the cost of the tax free items?
Rs. 15
Rs. 15.70
Rs. 19.70
Rs. 20
Answer: Option
Explanation:

Let the amount taxable purchases be Rs. x.

Then, 6% of x = 30
100

x = 30 x 100 = 5.
100 6

Cost of tax free items = Rs. [25 - (5 + 0.30)] = Rs. 19.70

Discussion:
101 comments Page 6 of 11.

Sweta said:   1 decade ago
I also think 20 is the right answer. Why do we have to deduct 30 paise?

V madhavaswamy said:   1 decade ago
Why you adding 30 paisa in final result in question no need mention any free tax. So why you added I can't understood.

Shivam said:   1 decade ago
19.70 Rs is the correct answer because it is given in question that total tax is 0.3 Rs.

Now by the given data as tax rate 6% we have to find how much amount is present in 25 Rs on which tax is imposed after calculation this simply tells us that there are 5 Rs items on which the tax of 0.3 Rs is imposed so now total amount is 5 Rs for items and 0.3 Rs tax on those items total is 5.3 Rs to find out price of non taxable.

Items we will deduct rs 5.3 from Rs 25.

SANDEEP said:   1 decade ago
Really I can't get any thing please any one explain me clearly.

Vipul said:   1 decade ago
Cost of stationary item is Rs. 25 which is included tax 30 paise.

So cost of item without tax is 25-0.30 = 24.70.

Now according to question let cost of item in which applying tax be X.

So 6% of X = 30/100 (because to convert paise into rupee divide by 100).

= 6/100*X = 30/100.

X = 5 rupees.

Now, cost of item with tax free = 24.70-5 = 19.70.

Eshu said:   10 years ago
There is an also another way.

1) The bought thing of Rs. 25.

2) 30 paise (0.030).

So subtract it 25-(0.030) = 24.7.

Then 30/6*100 = 30/6 = 5.

Subtract 24.7-5 = 19.7.

So here you get 19.7.

Prajyot said:   10 years ago
@Scarlet:

2) A container contains 30 litres of alcohol. From this container 5 litres of liquid is taken out and the container is completely filled by water. Next time 6 litres of mixture was taken out and the container was completely filled with water. Approx how much percent alcohol is left behind in the container?

5 litres removed from 30 liters.

>>> alcohol removed = 5(25/30).

= 4.16 liters.

>>> alcohol present = 25 - 4.16.

= 20.84 liters.

Now 6 liters removed from 30 liters.

>>> alcohol removed = 6 (20.84/30).

= 4.168 liters.

>>> alcohol present = 20.84 - 4.168.

= 16.67 liters.

Now we are asked % of alcohol present:

= 16.67 of 30.

= 16.67/30 * 100 = 55.56 %.

Manju said:   10 years ago
Tax = 6%.

There for tax = 6% of 24.7 (excluding 30 ps).

That is = 1. 482.

Therefore tax free = 25 - (1.482 + 0.3) = 23.218 know?

Shyam said:   10 years ago
Simple:

X be taxed items.
Y be non-taxed items.

Rs.25
Tax 30 Paise.
Tax 6%.

(6/100)X = (30/100).
X = 5.

Y = (25-(X+0.30)).
Y = 19.70.

Dezal said:   10 years ago
In a class 60% of students passed in Telugu, 50% 0f students passed in English. Then if every student Passed in either Telugu or English or both the subjects. Then what is the percentage of students passed in both the subjects?

Can anyone help me to solve this problem?


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