Aptitude - Percentage - Discussion
Discussion Forum : Percentage - General Questions (Q.No. 8)
8.
Two numbers A and B are such that the sum of 5% of A and 4% of B is two-third of the sum of 6% of A and 8% of B. Find the ratio of A : B.
Answer: Option
Explanation:
| 5% of A + 4% of B = | 2 | (6% of A + 8% of B) |
| 3 |
 |
5 | A + | 4 | B | = | 2 |  |
6 | A + | 8 | B |  |
| 100 | 100 | 3 | 100 | 100 |
| |
1 | A + | 1 | B | = | 1 | A + | 4 | B |
| 20 | 25 | 25 | 75 |
| |
|
1 | - | 1 | A = |
|
4 | - | 1 | B |
| 20 | 25 | 75 | 25 |
| |
1 | A = | 1 | B |
| 100 | 75 |
| A | = | 100 | = | 4 | . |
| B | 75 | 3 |
Required ratio = 4 : 3
Video Explanation: YouTube Video
Discussion:
52 comments Page 6 of 6.
Saranya said:
1 decade ago
sum of 5% of a and 4% of b = 5/100 * a + 4/100 * b
sum of 6% of A and 8% of B = 6/100 * a + 8/100 * b
5/100 * a + 4/100 * b =2/3 (6/100 * a + 8/100 * b)
3(5/100 * a + 4/100 * b)= 2 (6/100 * a + 8/100 * b)
15a/100 + 12b/100 = 12a/100 + 16b/100
(15a+ 12b)/100 = (12a + 16b)/100 (cancel 100)
15a + 12b = 12a + 16b
15a - 12a = 16b - 12b
3a = 4b
a/b = 4/3
a:b = 4:3
sum of 6% of A and 8% of B = 6/100 * a + 8/100 * b
5/100 * a + 4/100 * b =2/3 (6/100 * a + 8/100 * b)
3(5/100 * a + 4/100 * b)= 2 (6/100 * a + 8/100 * b)
15a/100 + 12b/100 = 12a/100 + 16b/100
(15a+ 12b)/100 = (12a + 16b)/100 (cancel 100)
15a + 12b = 12a + 16b
15a - 12a = 16b - 12b
3a = 4b
a/b = 4/3
a:b = 4:3
Shiva said:
1 decade ago
Any one can tell easy sol for this one?
(1)
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